The function which represents the taxi fare in terms of distance d in meter is f(d) = 3.50 ×
+ 40 .
According to the question,
For first 500 meters cost is 40.00 and For each additional 300 meters cost is 3.50 .
Let, the total distance of taxi ride = d meters
Now, representing the equation of taxi fare in terms of distance when distance is less than 500
taxi fare = 3.50 ×
+ 40
∴ f(d) = 3.50 ×
+ 40
To know more about functions refer below link: brainly.com/question/12431044
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Answer:
sorry I forgot try googling it
Answer:
−24x2+12xy+6x
Step-by-step explanation:
6x(2y−4x+1)
=(6x)(2y+−4x+1)
=(6x)(2y)+(6x)(−4x)+(6x)(1)
=12xy−24x2+6x