Answer:
x = amount of pure acid to be added = 6.67ml
Step-by-step explanation:
George wishes to increase the percent of acid in 50ml of a 15% acid solution in water to 25% acid, how much pure acid must you add?
let
x = amount of pure acid to be added
15% of 50 + x = 25% of 50 + x
(0.15 * 50) + x = 0.25(50 + x)
7.5 + x = 12.5 + 0.25x
Collect like terms
x - 0.25x = 12.5 - 7.5
0.75x = 5
x = 5/0.75
x = 6.6666666666666
Approximately,
x = 6.67
x = amount of pure acid to be added = 6.67ml
Answer:
25-9m^2-m+4m^3
= 4m^3-9m^2-m+25(Standard form)
This is a cubic polynomial since the degree of the polynomial is 3
Hope this helps!
Answer:
Step-by-step explanation:
sec(x)/csc(x) = (1/cos(x))/(1/sin(x))
= 1/cos(x) × sin(x)/1
= sin(x)/cos(x)
= tan(x)
Answer: 5/6 as a decimal is 0.83.
P(heads, and even and blue) = 1/2 *3/6 *1/4=1/2*1/2*1/4=1/16
P(heads, and 5, and green) = 1/2*1/6*1/4=1/48
P((heads or tail), and odd, and red)= (1/2+1/2)*3/6*1/4=1*1/2*1/4 = 1/8
P((heads or tail), and 3, and yellow)= (1/2+1/2)*1/6*1/4=1*1/6*1/4=1/24
P(tails, and prime, and not green) = 1/2 *3/6*3/4= 1/2*1/2*3/4=3/16
(Prime numbers here are 2,3 and 5)