Answer:
Molly's estimation was approximately correct.
Step-by-step explanation:
Given:
Diameter of bike tire = 2 feet
Also Given:
She estimated that for every turn of the tire, the bike traveled about 6 feet.
Estimated Distance traveled = 6 feet
We need to find that whether her estimation reasonable.
Solution:
Now we know that Distance traveled is equal to Circumference of tire.
Since Tire is in circular shape.
We can say that;
Circumference of the tire will be π times diameter.
framing in equation form we get;
Circumference of the tire = 
Now The actual distance traveled is 6.28 feet and Molly estimated as 6 feet.
Hence we can say that Molly's estimation was approximately correct.
The number of matinee movies attended is 4.
The number of a evening show movies attended is 2.
<u>Step-by-step explanation:</u>
- Let x represent the number of matinee movies attended.
- Let y represent the number of evening show movies attended.
- Alejandro went to see a total of 6 movies.
Therefore, from the given data the equation can be framed as :
⇒ x + y = 6 ----------(1)
- The cost of a matinee is $7.
- The cost of an evening show is $12.
- Alejandro spent a total of $52.
Therefore, from the given data the equation can be framed as :
⇒ 7x + `12y = 52 ---------(2)
<u>To solve the equations for x and y values :</u>
Mulitply eq (1) and by 7 and subtract eq (2) from eq (1),
7x + 7y = 42
- <u>(7x + 12y = 52)</u>
<u> - 5y = - 10 </u>
⇒ y = 10/5
⇒ y = 2
The number of a evening show movies attended is 2.
Substitute y=2 in eq (1),
⇒ x+2 = 6
⇒ x = 6-2
⇒ x = 4
The number of matinee movies attended is 4.
I think the correct answer is 17
The given expression is ![3b^2*(\sqrt[3]{54a}) + 3*(\sqrt[3]{2ab^6})](https://tex.z-dn.net/?f=%203b%5E2%2A%28%5Csqrt%5B3%5D%7B54a%7D%29%20%2B%203%2A%28%5Csqrt%5B3%5D%7B2ab%5E6%7D%29%20)
This can be simplified as :
= ![3*b^2*(\sqrt[3]{27 *2*a}) + 3*(\sqrt[3]{2*a*b^6})](https://tex.z-dn.net/?f=%203%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B27%20%2A2%2Aa%7D%29%20%2B%203%2A%28%5Csqrt%5B3%5D%7B2%2Aa%2Ab%5E6%7D%29%20)
We know that: ![\sqrt[3]{27} = 3](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B27%7D%20%20%3D%203%20%20%20)
Similarly we also can simplify: ![\sqrt[3]{b^6} = b^2](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7Bb%5E6%7D%20%20%3D%20b%5E2%20)
So our expression will look like this:
= ![3*3*b^2*(\sqrt[3]{2a}) + 3*b^2*(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%203%2A3%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20%2B%203%2Ab%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
= ![9b^2*(\sqrt[3]{2a}) + 3b^2*(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%209b%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20%2B%203b%5E2%2A%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
=![\sqrt[3]{2a}*(9b^2 + 3b^2)](https://tex.z-dn.net/?f=%20%20%5Csqrt%5B3%5D%7B2a%7D%2A%289b%5E2%20%2B%203b%5E2%29%20)
=![\sqrt[3]{2a}*(12b^2)](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B2a%7D%2A%2812b%5E2%29%20)
This can also be written as:
![12b^2(\sqrt[3]{2a})](https://tex.z-dn.net/?f=%2012b%5E2%28%5Csqrt%5B3%5D%7B2a%7D%29%20)
So the Answer is Option B
Just a guess, but the angle inside the triangle that's not x or y is the remaining angle after subtracting the 30 degrees shown. That makes the non labeled angle inside the triangle 150 degrees. since all triangles are 180 degrees, this means x and y add up to 30. They look roughly the same, so i'd guess they're both 15 degrees.