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grigory [225]
3 years ago
15

A shoe store orders shoes from the manufacturer and sells them at a mall. Storing shoes at the store costs $3 per shoe pair for

a year. When reordering shoes from the manufacturer, there is a fixed cost of $25 per order as well as $5 per shoe pair. The retail store sells 4500 shoe pairs each year. Find a function that models the total inventory costs as a function of x x the number of shoe pairs in each order from the manufacturer.
Mathematics
1 answer:
DerKrebs [107]3 years ago
3 0

Answer:

the function that models the total inventory costs as a function of x is;

$( \frac{112500}{x} + (\frac{3}{2})x )

Step-by-step explanation:

Given the data in the question;

cost of storing the shoes ( Holding cost ) = $ 3 per year

ordering cost ( Co ) fixed = $ 25 per order

cost of each pair = $ 5 per shoe pair

Total demand = 4500 shoe pairs

Total Inventory cost = Holding cost Ordering cost

so

Total Inventory cost = \frac{4500}{x}( $ 25) + \frac{1}{2}× $3 × x

Total Inventory cost = $( \frac{4500*25}{x} + (\frac{3}{2})x )

Total Inventory cost = $( \frac{112500}{x} + (\frac{3}{2})x )

Therefore, the function that models the total inventory costs as a function of x is; $( \frac{112500}{x} + (\frac{3}{2})x )

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horsena [70]

Answer:

$28.77

Step-by-step explanation:

If the subtotal is $27.14, and the tax to add is 6%, the total would be:

$27.14*(1+0.06)=$28.77

3 0
3 years ago
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Find the indicated limit, if it exists. limit of f of x as x approaches 9 where f of x equals x plus 9 when x is less than 9 and
SVEN [57.7K]

Answer:

B. 18

Step-by-step explanation:

For the function

f(x)=\left\{\begin{array}{l}x+9,\ \ x

we can find the value of the function for all x that are very close to 9 but are less than 9 and for all values of x that are very close to 9 but are greater than 9.

1. For x

\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(x+9)=9+9=18

2. For x\ge 9:

\lim \limits_{x\rightarrow 9}f(x)=\lim \limits_{x\rightarrow 9}(27-x)=27-9=18

So, limit exists and is equal to 18.

8 0
3 years ago
Land in downtown Columbia is valued at $10 a square foot. What is the value of a triangular lot with sides of lengths 119, 147,
stiks02 [169]

Answer:

$87,461

Step-by-step explanation:

Given that the dimensions or sides of lengths of the triangle are 119, 147, and 190 ft

where S is the semi perimeter of the triangle, that is, s = (a + b + c)/2.

S = (119 + 147 + 190) / 2 = 456/ 2 = 228

Using Heron's formula which gives the area in terms of the three sides of the triangle

= √s(s – a)(s – b)(s – c)

Therefore we have = √228 (228 - 119)(228 - 147)(228 - 190)

=> √228 (109)(81)(38)

= √228(335502)

=√76494456

= 8746.1109071 * $10

= 87461.109071

≈$87,461

Hence, the value of a triangular lot with sides of lengths 119, 147, and 190 ft is $87,461.

6 0
3 years ago
Whats 9+10? dont answer wrong
ozzi

19

Step-by-step explanation:

when we add 9 and 10 we will get sum 19

4 0
3 years ago
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Determine the value of a, b, and c for the quadratic equation: 4x2- 8x = 3
Rufina [12.5K]

Answer:

B. a = 4, b = -8, c = -3

Step-by-step explanation:

The quadratic equation given is:

4x^2- 8x = 3

The general form of a quadratic equation is given as:

ax^2 + bx +c = 0

Let us put the given equation in this form and then compare with the general form of the quadratic equation.

4x^2- 8x = 3\\\\4x^2 - 8x - 3 = 0

Therefore, by comparing:

a = 4

b = -8

c = -3

The correct option is B

4 0
3 years ago
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