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2 years ago

Quadrilateral ABCD has diagonals that are congruent and perpendicular to each other. What classification can be given to ABCD?

Mathematics

2 answers:

DENIUS [597]2 years ago

8 0

Actually the correct answer would be a rhombus

Andreyy892 years ago

7 0

ABCD can be classified as a square.

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I need your help broskis

Ilia_Sergeevich [38]

a very fast way to do it:

Trivially 8.8*5>10, so the power of 10 is 6+2+1 = 9.

Therefore, the answer is $\boxed{4.4 \text{ x }10^9}$

8 0

2 years ago

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What is the length of BC , rounded to the nearest tenth?

Arte-miy333 [17]

Step $1$

In the right triangle ADB

Find the length of the segment AB

Applying the Pythagorean Theorem

$AB^{2} =AD^{2}+BD^{2}$

we have

$AD=5\ units\\BD=12\ units$

substitute the values

$AB^{2}=5^{2}+12^{2}$

$AB^{2}=169$

$AB=13\ units$

Step $2$

In the right triangle ADB

Find the cosine of the angle BAD

we know that

$cos(BAD)=\frac{adjacent\ side }{hypotenuse}=\frac{AD}{AB}=\frac{5}{13}$

Step $3$

In the right triangle ABC

Find the length of the segment AC

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

$AC=(13*13)/5=33.8\ units$

Step $4$

Find the length of the segment DC

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

Find the length of the segment BC

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

we have

$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

$BC=31.2\ units$

therefore

the answer is

$BC=31.2\ units$

8 0

2 years ago

Read 2 more answers

What's two equivalent from of3/5

jolli1 [7]

6/10
300/500
30/50
60/100
12/20

4 0

3 years ago

Which of these is a geometric sequence?

11Alexandr11 [23.1K]

Answer:

The correct answer is D

Step-by-step explanation:

7 0

3 years ago

Line segment GT contains the point G(−3, 5) and a midpoint at A(1, −4). What is the location of endpoint T?

algol [13]

Imagine you're moving along the segment. Since the midpoint is in the middle of the segment (obviously), it means that when you've traveled from G to A, you're halfway through your journey, along both x and y directions. So, let's break the problem in two and analyze both directions.

Along the x axis, you've moved from -3 to 1, so you moved 4 units forward. This means that you have 4 units still to go, and your journey will end at coordinate 5.

Similarly, along the y axis, you've moved from 5 to -4, so you moved 9 units downward. This means that you have 9 units still to go, and your journey will end at coordinate -13.

So, the coordinates of the endpoint are $T = (5,-13)$