Quadrilateral ABCD has diagonals that are congruent and perpendicular to each other. What classification can be given to ABCD?
2 answers:
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By definition, the unit vector of v = (a,b) is
Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
(3,5)/√[3² + 5²]
= (3,5)/√34
The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65
Answer:
The unit vector of v₁ in the direction of |v₁} is
The unit vector of v₂ in the directin of |v₂| is
Therefore,
The unit vector of v₁ = (3,5) in the direction of |v₁| s
(3,5)/√[3² + 5²]
= (3,5)/√34
The unit vector of v₂ in the direction of |v₂| is
(-4,7)/√[(-4)² + 7²]
= (-4,7)/√65
Answer:
The unit vector of v₁ in the direction of |v₁} is
The unit vector of v₂ in the directin of |v₂| is
Answer:
<em>(1, - 2) </em>
Step-by-step explanation:
2x - y = 4
3x + y = 1
A = = 2(1) - 3( - 1) =2 + 3 = 5
=
= 4(1) - 1(- 1) = 4 + 1 = 5
=
= 2(1) - 4(3) = 2 - 12 = - 10
<em>x </em>= =<em> 1</em>
<em>y </em>= = <em>- 2</em>
<em>(1, - 2)</em>