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solniwko [45]
3 years ago
13

Quadrilateral ABCD has diagonals that are congruent and perpendicular to each other. What classification can be given to ABCD?

Mathematics
2 answers:
DENIUS [597]3 years ago
8 0
Actually the correct answer would be a rhombus
Andreyy893 years ago
7 0
ABCD can be classified as a square.
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I need help with this problem it’s due at midnight and I’m so tired of trying. Thanks it’s number 4 btw
bearhunter [10]

Answer:

Look below

Step-by-step explanation:

A.

8 + 9 + 10 = 27

9 + 10 + 11 = 30

10 + 11 + 12 = 33

B. Every answer is divisible by 3, every consecutive answer is also 3 more than the one before it.

C. Yes

19 + 20 + 21 = 60

D. No

8 is not divisible by 3. Also, the closest you can get is 6 (1 + 2 + 3) or 9 (2 + 3 + 4).

I hope this helped! If you need anything else, let me know in the comments. :)

6 0
3 years ago
CAN SOMEONE HELP ME WITH THIS PLEASE AND THANK YOU.
Mariana [72]

Answer:

11 2/3

Step-by-step explanation:

2 1/3 * 5

Change the mixed number to an improper fraction

2 /13 = ( 3*2+1)/3  = 7/3

7/3 * 5/1

35/3

Now change it back to a mixed number

3 goes back into 35 11 times with 2 left over

11 2/3

8 0
2 years ago
Read 2 more answers
2(n+7)=14+2n and 1-x=7x-(8x-6)
myrzilka [38]
2n+14=14+2n so this one as an infinite number of solutions. The second one 1-x=-x-6 so you add x on both sides which results in it having no solutions.
3 0
3 years ago
each of exercises 15–30 gives a function ƒ(x) and numbers l, c, and e 7 0. in each case, find an open interval about c on which
3241004551 [841]

The given inequality holds for the open interval (2.97,3.03)

It is given that

f(x)=6x+7

cL=25

c=3

ε=0.18

We have,

|f(x)−L| = |6x+7−25|

          = |6x−18|

          = |6(x−3)|

          = 6|x−3|

Now,

6|x−3| <0.18  then |x−3|<0.03 ----->−0.03<x-3<0.03---->2.97<x<3.03

the given inequality holds for the open interval (2.97,3.03)

For more information on inequality click on the link below:

brainly.com/question/11613554

#SPJ4

Although part of your question is missing, you might be referring to this full question: For the given function f(x) and values of L,c, and ϵ0, find the largest open interval about c on which the inequality |f(x)−L|<ϵ holds. Then determine the largest value for δ>0 such that 0<|x−c|<δ→|f(x)−|<ϵ.

f(x)=6x+7,L=25,c=3,ϵ=0.18

 

.

6 0
2 years ago
What's the answer for this skaldnwkdnskdnskxn
Blizzard [7]
Which one they both is really easy
7 0
3 years ago
Read 2 more answers
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