Answer:
Step-by-step explanation:
Let c represent Chanda's age now. In six years, the Sokhem's age will be 2c. At that time, the sum of their ages is ...
(c+6) +2c = 60
3c = 54 . . . . . . . . subtract 6, collect terms
c = 18 . . . . . . . . . . divide by 3
Chanda is 18, Sokhem is 30.
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<em>Check</em>
In 6 years Chanda will be 24, Sokhem will be 36. The sum of their ages then will be 24+36 = 60. Since Chanda is 18 now, Sokhem's age then will be 2 times Chanda's age now.
Given that the original length of the baguette is 65, and for each day 15 gets cut off, we have the function
l(d) = 65 - 15d
where d is a positive integer representing the nth day. As a matter of fact, the possible vaalues for d are 0, 1, 2, 3, and 4. Since on the 5th day, there won't be enough baguette anymore. This shows that the function l(d) is not continous since only certain points satisfy the condition.
Thus, the function is l(d) = 65 - 15 where {d| 0 ≤ d ≤ 4} and it is discrete<span>.</span>
Answer:
x = 2; y = 3; z = 1
Step-by-step explanation:
For the first fertilizer (A) we can form the equation:
y + 2z = 5
For the second fertilizer (B) we can form the equation:
x + 2y + 5z = 13
For the third fertilizer (C) we can form the equation:
x + 2z = 4
solving simulteneously:
y = 5 - 2z
x = 4 -2z
Substituting (i) and (ii) into (2)
4 - 2z + 10 -4z + 5z = 13
14-z =13, therefore z = 1
substituting z into (i) and (ii)
y = 3
x = 2
Answer:
the area is 6.5
Step-by-step explanation:
