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2 years ago

I need help please help me

Mathematics

2 answers:

Klio2033 [76]2 years ago

7 0

Answer:

A, D, B

Step-by-step explanation:

The roots (zeroes) are the x values where the graph intersects the x-axis. To find the roots(zeroes), replace y with 0 and solve for x.

gulaghasi [49]2 years ago

3 0

Answer:

A, B and D

Step-by-step explanation:

The zeros of f(x) are the points located on the x- axis, that is where y = 0

We can check which ones are the solutions by finding the zeros of f(x)

To find the zeros let f(x) = 0 , that is

(x² + 2x - 8)(x - 6) = 0 ← factorise the quadratic

(x + 4)(x - 2)(x - 6) = 0

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

x - 2 = 0 ⇒ x = 2

x - 6 = 0 ⇒ x = 6

There are 3 zeros at x = - 4, x = 2, x = 6

These are located at A, B and D

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<h2>Explanation:</h2>

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<u>Slope:</u>

$\text{For AB}: \\ \\ m=\frac{5-3}{1-(-1)}=1 \\ \\ \\ \text{For CD}: \\ \\ m=\frac{1-(-1)}{5-3}=1 \\ \\ \\ \text{So AB and CD are parallel}$

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$\text{For BC}: \\ \\ m=\frac{1-5}{5-1}=-1 \\ \\ \\ \text{For AD}: \\ \\ m=\frac{-1-3}{3-(-1)}=-1 \\ \\ \\ \text{So BC and AD are parallel}$

So in fact this is a parallelogram. The other thing we need to prove is that the diagonals measure the same. Using distance formula:

$d=\sqrt{(y_{2}-y_{1})^2+(x_{2}-x_{1})^2} \\ \\ \\ Diagonal \ BD: \\ \\ d=\sqrt{(5-(-1))^2+(1-3)^2}=2\sqrt{10} \\ \\ \\ Diagonal \ AC: \\ \\ d=\sqrt{(3-1)^2+(-5-1)^2}=2\sqrt{10} \\ \\ \\$

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Step-by-step explanation:

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