Answer:
The expected value of the safe bet equal $0
Step-by-step explanation:
If
is a finite numeric sample space and
for k=1, 2,..., n
is its probability distribution, then the expected value of the distribution is defined as
What is the expected value of the safe bet?
In the safe bet we have only two possible outcomes: head or tail. Woodrow wins $100 with head and “wins” $-100 with tail So the sample space of incomes in one bet is
S = {100,-100}
Since the coin is supposed to be fair,
P(X=100)=0.5
P(X=-100)=0.5
and the expected value is
E(X) = 100*0.5 - 100*0.5 = 0
Answer:
need a diagram to be able to answer
Step-by-step explanation:
Answer: 24
8 oz is half a pound because a pound is 16 oz, so if you count how many halves go into 12 lbs you get 24 bags
Answer:
11/4 seconds
Step-by-step explanation:
We can see from the given equation that the height at the diving board is h = 3.
This is because the h(t) equation has that +3 at the end, which denotes the initial height of the diver, the height when he is standing on the board before jumping.
To find where h(t) = 3 is true, we need to set h(t) equal to 3 and solve for t.
h(t) = 3
h(t) = -4t^2 + 11t + 3 = 3
-4t^2 + 11t + 3 - 3 = 0
-4t^2 + 11t = 0
t*(-4t + 11) = 0
so h(t) = 3 when t = 0 and when t = 11/4 sec
we already know that at t = 0 the height is 3, it is the initial height given from the equation, so we want to use the other solution for t.
the diver is back at the height of the diving board at t = 11/4 sec
Multiply to remove the variable from the denominator.
