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2 years ago

C) Parbati buys a mobile for Rs 6,300 and sells it to Laxmi at 15% profit. How much

Mathematics

1 answer:

Leni [432]2 years ago

6 0

Answer:

Rs. 7245

Step-by-step explanation:

Given parameters:

Cost price = Rs. 6300

Percentage profit = 15%

Unknown:

Selling price = ?

Solution:

If profit is made on a trade, the selling price is higher than the cost price.

Profit = Selling price - Cost price

To find the selling price simply;

Selling price =( 1 + $\frac{15}{100}$ ) x cost price

Selling price = 1.15 x 6300 = Rs. 7245

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3 years ago

Evaluate N^2 + 2N 1 for N=5

Murljashka [212]

Answer:

Step-by-step explanation:

write 5 in N's place

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25+10

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2 years ago

A gas station sells unleaded regular and unleaded premium gasoline. The price per gallon charged by the station is$1.299 for unl

Jet001 [13]

Answer:

a) Revenue function = 1.299r + 1.379p

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2 years ago

0/1 Hannah went to the store and spent $14. 69 on a book, $20. 99 on a shirt, and $5. 99 on a pack of pencils. If she paid with

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Answer:

$8.33

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$14.69 50.00

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2 years ago

Combine the following expressions.

Keith_Richards [23]

Answer:

second option

Step-by-step explanation:

Using the rule of radicals

$\sqrt{a}$ × $\sqrt{b}$ ⇔ $\sqrt{ab}$

Simplifying the radicals

$\sqrt{27x^{3} }$

= $\sqrt{9(3)x^2.x}$

= $\sqrt{9}$ × $\sqrt{3}$ × $\sqrt{x^2}$ × $\sqrt{x}$

= 3 × $\sqrt{3}$ × x × $\sqrt{x}$

= 3x $\sqrt{3x}$

-------------------------------

$\sqrt{12x^{3} }$

= $\sqrt{4(3)x^2.x}$

= $\sqrt{4}$ × $\sqrt{3}$ × $\sqrt{x^2}$ × $\sqrt{x}$

= 2 × $\sqrt{3}$ × x × $\sqrt{x}$

= 2x $\sqrt{3x}$

---------------------------------------

Thus

3 × 3x $\sqrt{3x}$ - 2 × 2x $\sqrt{3x}$

= 9x $\sqrt{3x}$ - 4x $\sqrt{3x}$

= 5x $\sqrt{3x}$

8 0

3 years ago