What is the approximate area of the regular pentagon?

Mathematics

2 answers:

Anastasy [175]3 years ago

7 0

Area of the pentagon: 342 cm2

Step-by-step explanation:

The figure of the pentagon is missing: find it in attachment.

The area of the pentagon can be seen as the area of 5 equal triangles, each of them having a base equal to the length of the side of the pentagon,

L = 14.1 cm

and the height of each triangle can be found by using Pythagorean's theorem:

$h=\sqrt{12^2-(\frac{L}{2})^2}=\sqrt{12^2-(\frac{14.1}{2})^2}=9.7 cm$

The area of each of the 5 triangles is

$A'=\frac{1}{2}Lh$

Therefore, the area of the pentagon is 5 times this area:

$A=5A'=\frac{5}{2}Lh=\frac{5}{2}(14.1)(9.7)=342 cm^2$

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Zolol [24]3 years ago

7 0

Answer:

342 cm2

Step-by-step explanation:

got 100%

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determine if the sequence is geometric if it is find the common ratio the 8th term and the explicit formula can someone check my

mylen [45]

Answer:

You can check the answer by yourself after seeing the below answer.

Step-by-step explanation:

A sequence is geometric only if has common ratio i.e. $r=\frac{a2}{a1} =\frac{a3}{a2}$ whiere a1,a2 and a3 are first,second and third term of the sequence respectively.

1) Common ratio $r=\frac{-18}{-3}=\frac{-108}{-18}=6\\$

Explicit formula $a_{n} =a_{1} .r^{n-1}$

Now using the above formula, we can find $8^{th} term=-3*(6)^{8-1} =-3*6^{7}=-839808.$

2) Here

$\frac{a2}{a1}\neq \frac{a3}{a2}\\\frac{-2}{-4}\neq \frac{1}{-2}\\\frac{1}{2}\neq\frac{1}{-2}$ so this is not geometric sequence so no need to proceed further.