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VikaD [51]
3 years ago
7

What is the approximate area of the regular pentagon?

Mathematics
2 answers:
Anastasy [175]3 years ago
7 0

Area of the pentagon: 342 cm2

Step-by-step explanation:

The figure of the pentagon is missing: find it in attachment.

The area of the pentagon can be seen as the area of 5 equal triangles, each of them having a base equal to the length of the side of the pentagon,

L = 14.1 cm

and the height of each triangle can be found by using Pythagorean's theorem:

h=\sqrt{12^2-(\frac{L}{2})^2}=\sqrt{12^2-(\frac{14.1}{2})^2}=9.7 cm

The area of each of the 5 triangles is

A'=\frac{1}{2}Lh

Therefore, the area of the pentagon is 5 times this area:

A=5A'=\frac{5}{2}Lh=\frac{5}{2}(14.1)(9.7)=342 cm^2

Learn more about area of regular figures:

brainly.com/question/4599754

brainly.com/question/3456442

brainly.com/question/6564657

#LearnwithBrainly

Zolol [24]3 years ago
7 0

Answer:

342 cm2

Step-by-step explanation:

got 100%

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I will 10 points pls anwser correct
coldgirl [10]

Answer:

1.5 if you Evaluate and in fraction form \frac{15}{10}

4 0
2 years ago
How many different 5​-letter radio station call letters can be made a. if the first letter must be Upper C comma Upper X comma U
Lady_Fox [76]

Answer:

a) 1,518,000

b) 2,284,880

c) 60,720

Step-by-step explanation:

a) a. if the first letter must be Upper C comma Upper X comma Upper T comma or Upper M and no letter may be​ repeated?

We draw 5 boxes, and based on that we will see the total possible cases. There are 26 alphabets

The first box should have C or X or T or M .No letter may be repeated.

Any                    Any             Any                 Any                    Any

5 alphabets    of the            of the              of the                 of the

C,X , T , M      remaining     remaining       remaining          remaining

                   25 alphabets   24 alphabets   23 alphabets   22 alphabets

Therefore; total possible call letters = 5 × 25 × 24 × 23 × 22 = 1,518,000

b)

The first box should have C or X or T or M Repeats as allowed

Any                    Any             Any                 Any                    Any

5 alphabets    of the            of the              of the                 of the

C,X , T , M      remaining     remaining       remaining          remaining

                   26 alphabets   26 alphabets   26 alphabets   26 alphabets

Therefore Total possible call letters = 5 × 26 × 26 × 26 × 26 = 2,284,880

c)   The first box should have   C,X , T , M  and end with S

So the last place if fixed, and we now have 25 alphabets. The first box can go in 5 ways. The next box then will have only 24 letters to choose from, as the first box has taken a letter and the last box already has S in it. Repetition not allowed

Any                    Any             Any                 Any                       S

5 alphabets    of the            of the              of the                  is fixed

C,X , T , M      remaining     remaining       remaining           here

                   24 alphabets   23 alphabets   22 alphabets  

Therefore Total possible call letters = 5 × 24 × 23 × 22  × 1 =  60,720

3 0
3 years ago
A soccer field is a rectangle 48 meters wide and 55 meters long. The coach asks players to run from one corner to the corner dia
Sindrei [870]

Answer:

Distance = 73 m

Step-by-step explanation:

Given that,

The length of a rectangle = 48 m

The width of a rectangle = 55 m

We need to find the diagonal distance. We can use the Pythagoras theorem to find it.

d^2=48^2+55^2\\\\d=\sqrt{5329}\\\\d=73\ m

So, the required distance is equal to 73 m.

5 0
3 years ago
10×3 tens in standard form
tamaranim1 [39]

The answer to that would be 30

5 0
4 years ago
Read 2 more answers
Simplify the expression
asambeis [7]

Answer:

B

Step-by-step explanation:

given

- 4x²(3x - 7)

multiply each term in the parenthesis by - 4x²

= (-4x² × 3x) + ( - 4x² × - 7)

= - 12x³ + 28x² → B



6 0
3 years ago
Read 2 more answers
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