Can someone find x for these questions

Mathematics

1 answer:

Maurinko [17]3 years ago

8 0

Answer:

8, 36, -12

Step-by-step explanation:

41 = 8x - 23

8x = 41 + 23

8x = 64

x = 8

11 = x/2 - 7

22 = x - 14

22 + 14 = x

x = 36

3(x - 8) = -60

x - 8 = -20

x = -12

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A personnel director interviewing 12 senior engineers for five job openings has scheduled seven interviews for the first day and

bezimeni [28]

Answer:

a) h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)

b) 2.92

Step-by-step explanation:

Here

Number of interviewees = N = 12

Number of job openings = M = 5

Interviews schedules for the first day = n = 7

N − M = 12 - 5 = 7

Using hypergeometric distribution:

Let X be the no. top four candidates interviewed on first day.

The probability mass function of X:

P(X = x) = $(^{M} C_{x})$ $(^{N-M} C_{n-x})$ / $(^{N} C_{n})$

It can be written as:

h(x; n, M, N) = $(^{M} C_{x})$ $(^{N-M} C_{n-x})$ / $(^{N} C_{n})$

= (5Cx) (7C7-x) / (12C7)

= (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)

h(x; 7, 5, 12) = (⁵Cₓ)( ⁷C₇₋ₓ) / (¹²C₇)

The expectation is: E(X) = np

E(X) = n * M/N

= 7 * 5/12

= 7 * 0.41667

= 2.9167

6 0

3 years ago

. (06.02)

lora16 [44]

Answers:

1.) C - Final exams: midterm = Q3 92 - Q1 80 = 12 and finals = Q3 85 - Q1 78 = 7, so finals exam has the smaller IQR.

2.) B - exam median is much higher than the class median: refer to the attached image of class and exam box and whisker graph

3.) A - IQR is a better measure of spread for movies than it is for basketball games: because the data for movies are quite wide or apart from each other than the data in the basketball games

4.) A - mean for April is higher than October's mean: mean in April is 67 and mean in October is 60

5.) A - Neither data set has suspected outliers: meaning there's no data that is further apart from the group or set

6.) B - There is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical

7.) C - college spread is best described by the IQR. The high school spread is best described by the standard deviation: this is because of the wide range of data in the college than the data in the high school.