The maximum value of the objective function is 26 and the minimum is -10
<h3>How to determine the maximum and the minimum values?</h3>
The objective function is given as:
z=−3x+5y
The constraints are
x+y≥−2
3x−y≤2
x−y≥−4
Start by plotting the constraints on a graph (see attachment)
From the attached graph, the vertices of the feasible region are
(3, 7), (0, -2), (-3, 1)
Substitute these values in the objective function
So, we have
z= −3 * 3 + 5 * 7 = 26
z= −3 * 0 + 5 * -2 = -10
z= −3 * -3 + 5 * 1 =14
Using the above values, we have:
The maximum value of the objective function is 26 and the minimum is -10
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Answer:
C
Step-by-step explanation:
First check if the triangle is right.
If the square of the longest side is equal to the sum of the squares on the other 2 sides then the triangle is right.
longest side =
and (
)² = 12
2² + (
)² = 4 + 8 = 12
Thus the triangle is right → C
Answer:
7
Step-by-step explanation:
Y is directly proportional to x and therefore takes the form y=kx where k is the constant of proportionality.
Dividing both sides by x for the given values, k becomes 18/4 = 4.5
Answer: The answer is B(0,3)
Step-by-step explanation: I took the test and made sure it was correct