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2 years ago

Figure A is a scale image of Figure B. What is the value of x? Pls answer asap!

Mathematics

1 answer:

Alexeev081 [22]2 years ago

8 0

Answer: Answer: The required value of x is 12 units.

Step-by-step explanation: Given that the figure A is a scale image of figure B.

We are to find the value of x.

Since figure A is the scale image of figure B, so both the figures are similar to each other.

Also, the corresponding sides of the similar figures are proportional, so we get

Thus, the required value of x is 12 units.

Step-by-step explanation:

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The area of a rectangle is 162/3 ft2 . The length is 61/4 . Find the width. Show all work

brilliants [131]

Answer:

I have gotten 216/61, but I am not sure if this is right.

Step-by-step explanation:

By using the "Keep It, Change It, Flip It" tactic, I was able to come up with an answer and simplify it.

1. Keep the original divisor.

162/3

2. Change the sign.

Division becomes multiplication.

3. The last fraction is reciprocated.

61/4 becomes 4/61.

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2 years ago

Please answer the picture below!

Margarita [4]

3e-1.5f-.375 is the answer.

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2 years ago

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Please answer correctly! I will mark Brainliest!

Pie

Answer:

its 60 all around

Step-by-step explanation:

5 0

3 years ago

Un jardín rectangular de 50 cm de largo por 34 m de ancho está rodeado por un camino de arena uniforme.Halla la anchura de dicho

Anastasy [175]

Answer:

5.85 m

Step-by-step explanation:

The width of the sand road can be calculated knowing its area and the dimensions of the rectangular garden as follows:

$A_{g} = a.b$

<u>Where:</u>

Ag: is the area of the rectangular garden

a: is the length of the rectangular garden = 50 cm = 0.5 m

b: is the width of the rectangular garden = 34 m

$A_{s} = 540 m^{2}$

<u>Where</u>:

As: is the area of the sand road

The relation between the area of the sand road and the area of the rectangular garden is the following:

$A_{s} + A_{g} = (a+2x)*(b+2x)$

$540 m^{2} + 0.5m*34m = ab + 2ax + 2bx + 4x^{2}$

$557 m^{2} = ab + 2x(a + b) + 4x^{2}$

$557 m^{2} - 17m^{2} - 2x(34.5 m) - 4x^{2} = 0$

$540 - 69x - 4x^{2} = 0$

By solving the above equation for x we have two solutions:

x₁ = -23.10 m

x₂ = 5.85 m

Taking the positive value, we have that the width of the sand road is 5.85 m.

I hope it helps you!

7 0

3 years ago

I need help please and thank you ( show your work please)

Bas_tet [7]

Answer:

y = 2x

Step-by-step explanation:

Use Rise over Run. The rise(up/down) is 2 and the run(sideways) is 1. The slope is going up, not down so the 2 is positive. So, it is positive 2/1, which you can write as 2.

7 0

1 year ago