HELPP ITS IMPORTANT

a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream

Nonamiya [84]

the coordinates where the bridges must be built is $(3,-6)$ and $(6,3)$ .

Step-by-step explanation:

Here we have , a road follows the shape of a parabola f(x)=3x2– 24x + 39. A road that follows the function g(x) = 3x – 15 must cross the stream at point A and then again at point B. Bridges must be built at those points.We need to find Identify the coordinates where the bridges must be built. Let's find out:

Basically we need to find values of x for which f(x) = g(x) :

⇒ $f(x)-g(x)=0$

⇒ $3x^2- 24x + 39-(3x - 15 ) =0$

⇒ $3x^2- 24x + 39-3x + 15 =0$

⇒ $3x^2- 27x + 54 =0$

⇒ $x^2- 9x + 18 =0$

⇒ $x^2- 6x-3x + 18 =0$

⇒ $x(x- 6)-3(x - 6) =0$

⇒ $(x-3)(x- 6) =0$

⇒ $x=3 , x=6$

Value of g(x) at x = 3 : y=3x -15 = 3(3)-15 = -6

Value of g(x) at x = 6 : y=3x -15 = 3(6)-15 = 3

Therefore , the coordinates where the bridges must be built is $(3,-6)$ and $(6,3)$ .

7 0

3 years ago

Find the length of side x to the nearest tenth

navik [9.2K]

Answer:

x = 2 sqrt(3)/3

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opp / hyp

sin 60 = 1 /x

x sin 60 =1

x = 1 /sin 60

x = 1 / sqrt(3)/2

x = 2 sqrt(3)/3

3 0

2 years ago

If mAGF = mBGC = mDGC = mEGF = 70°, what is mAGB? A.40° B.70° C.110° D.35°

Tresset [83]

B it's going to work

7 0

3 years ago

A rectangular box has a base that is 4 times as long as it is wide. The sum of the height and the girth of the box is 200 feet.

enyata [817]

Answer: V(W) = (1/3)*(*W^2*800ft - 8W^3) and the domain is 0 < W < 100ft.

Step-by-step explanation:

The dimensions of the box are:

L = length

W = width

H = heigth.

We know that:

L = 4*W

And the girth of a box is equal to: G = 2*W + 2*H

then we have:

2*W + 2*H + H = 200ft

2W + 3*H = 200ft

Then we have two equations:

L = 4*W

2W + 3*H = 200ft

We want to find the volume of the box, which is V = W*L*H

and we want in on terms of W.

Then, first we can replace L by 4*W (for the first equation)

and:

2*W + 3*H = 200ft

3*H = 200ft - 2*W

H = (200ft - 2*W)/3.

then the volume is:

V(W) = W*(4*W)*(200ft - 2*W)/3

V(W) = (1/3)*(*W^2*800ft - 8W^3)

The domain of this is the set of W such that the volume is positive, then we must have that:

W^2*800ft > 8W^3

To find the maximum W we can see the equality (the minimum extreme is 0 < W, because the width can only be a positive number)

W^2*800ft = 8W^3

800ft = 8*W

100ft = W.

This means that if W is equal or larger than 100ft, the equation gives a negative volume.

Then the domain is 0 < W < 100ft.

6 0

3 years ago

Based on the dartboard shown below, what is P(pink and even)

Greeley [361]

Answer:

1/8

Step-by-step explanation:

There are 8 slots and only one of them is pink and even

5 0

3 years ago

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