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3 years ago

HELPP ITS IMPORTANT

Mathematics

1 answer:

Misha Larkins [42]3 years ago

4 0

H times how your payrate

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Find the volume.!!.!

zhuklara [117]

Answer:

The image is blurry for me

Step-by-step explanation:

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2 years ago

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Simplify (7)(-6). need help

dexar [7]

As simple as it can go is As it's multiplied out form, which is -42.

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3 years ago

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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago

Luther evaluated 2^3 as 9 and wade evaluated 3^2 as 9 are both students correct?

MatroZZZ [7]

Answer:

Step-by-step explanation:

Luther is incorrect. 2 x 2= 4 x 2 = 8 (not 9)

1 2 3

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3 years ago

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The admissions office of a private university released the following admission data for the preceding academic year: From a pool

lina2011 [118]

Answer: Our required probability is 0.1695.

Step-by-step explanation:

Since we have given that

Number of male applicants = 4200

Number of female applicants = 3800

So, total number of applicants = 4200+3800 = 8000

Probability of male entered and subsequently enrolled is given by

$0.4\times 0.4=0.16$

Probability of female entered and subsequently enrolled is given by

$0.4\times 0.45\\\\=0.18$

Number of male entered and subsequently enrolled is given by

$0.16\times 4200\\\\=672$

Number of female entered and subsequently enrolled is given by

$0.18\times 3800\\\\=684$

So, Probability that a student who applied for admission will be accepted by the university and subsequently will enroll is given by

$\dfrac{672+684}{8000}\\\\=\dfrac{1356}{8000}\\\\=0.1695$

Hence, our required probability is 0.1695.

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3 years ago