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saveliy_v [14]
2 years ago
8

Han says that you can wrap a 5-foot rope around a wheel with a 2-foot diameter because is less than pi. Do you agree with Han? C

opied for free from openupresources.Org
Mathematics
2 answers:
TEA [102]2 years ago
6 0

agree Step-by-step explanation:

madam [21]2 years ago
3 0

Given :

Han says that we can wrap a 5 foot rope around a wheel with a 2 foot rope.

To Find :

It this true or false.

Solution :

Radius of wheel, r = 1 foot.

Circumference of wheel is given by :

C = 2\pi r\\\\C = 2\times 3.14\times 1\\\\C = 6.28 \ foot

Since, circumference is greater than 5 foot, therefore, we cannot wrap a  5-foot rope around a wheel with a 2-foot diameter.

Hence, this is the required solution.

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A store selling newspapers orders only n = 4 of a certain newspaper because the manager does not get many calls for that publica
umka2103 [35]

Answer:

a) The expected value is 2.680642

b) The minimun number of newspapers the manager should order is 6.

Step-by-step explanation:

a) Lets call X the demanded amount of newspapers demanded, and Y the amount of newspapers sold. Note that 4 newspapers are sold when at least four newspaper are demanded, but it can be <em>more</em> than that.

X is a random variable of Poisson distribution with mean \mu = 3 , and Y is a random variable with range {0, 1, 2, 3, 4}, with the following values

  • PY(k) = PX(k) = ε^(-3)*(3^k)/k! for k in {0,1,2,3}
  • PY(4) = 1 -PX(0) - PX(1) - PX(2) - PX (3)

we obtain:

PY(0) = ε^(-3) = 0.04978..

PY(1) = ε^(-3)*3^1/1! = 3*ε^(-3) = 0.14936

PY(2) = ε^(-3)*3^2/2! = 4.5*ε^(-3) = 0.22404

PY(3) = ε^(-3)*3^3/3! = 4.5*ε^(-3) = 0.22404

PY(4) = 1- (ε^(-3)*(1+3+4.5+4.5)) = 0.352768

E(Y) = 0*PY(0)+1*PY(1)+2*PY(2)+3*PY(3)+4*PY(4) =  0.14936 + 2*0.22404 + 3*0.22404+4*0.352768 = 2.680642

The store is <em>expected</em> to sell 2.680642 newspapers

b) The minimun number can be obtained by applying the cummulative distribution function of X until it reaches a value higher than 0.95. If we order that many newspapers, the probability to have a number of requests not higher than that value is more 0.95, therefore the probability to have more than that amount will be less than 0.05

we know that FX(3) = PX(0)+PX(1)+PX(2)+PX(3) = 0.04978+0.14936+0.22404+0.22404 = 0.647231

FX(4) = FX(3) + PX(4) = 0.647231+ε^(-3)*3^4/4! = 0.815262

FX(5) = 0.815262+ε^(-3)*3^5/5! = 0.91608

FX(6) = 0.91608+ε^(-3)*3^6/6! = 0.966489

So, if we ask for 6 newspapers, the probability of receiving at least 6 calls is 0.966489, and the probability to receive more calls than available newspapers will be less than 0.05.

I hope this helped you!

8 0
3 years ago
Please help! Sketch the graph of each line.
madam [21]

Answer:

1) (-3,0) (0,-3)

2) (-2,0)

3) (5,0) (0,-1)

4) (12,0) (0,3)

5) (-16,0) (0,4)

6) (-0.8333,0) (0,5)

4 0
3 years ago
Find the midpoint of (-5,12) and (3,-6)
exis [7]

Answer:

mid point: (4,5)

hope that helps :)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Rachel is a lunchroom supervisor at west school the children eat lunch at 15 long tables. When all tables used 240 children can
ahrayia [7]
16 seats at each table
4 0
3 years ago
Read 2 more answers
Gaetano spent $37.80, including tax, on a pair of jeans. How much did the jeans cost if there was an 8% sales tax? And what is t
Galina-37 [17]
37.8*0.08=3.024
37.8-3.024=34.776
round to the nearest tenths place for currency
and the answer is $34.78
6 0
3 years ago
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