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Alex777 [14]
3 years ago
13

Teisha is saving for a $3,150 car. If she can save $350 every month, how many months will it take her to save the amount she nee

ds? Create a relation for the total amount saved, T, after m months and then solve for the number of months. Select all answers that apply.
A. T(m) = 350m
B. T(m) = 350+m
C. T(m) = 350-m
D. 8 Months
E. 9 Months
F. 10 Months
G. 7 Months
H. T(m) = 350/m
Mathematics
1 answer:
Annette [7]3 years ago
5 0

Answer:

E: 9 months

Step-by-step explanation:

You might be interested in
Consider the function f(x)=x3+6x2−20x+450.
Damm [24]

Answer:

Therefore reminder = 2802

Step-by-step explanation:

f(x)=x³+6x²-20x+450

x-12)x³+6x²-20x+450(x²+18x+196

      x³-12x²

    ____________________

          +18x²-20x+450

           18x²-216x

          _______________

                  196x +450

                  196x-2352

                 _____________

                            2802

Therefore reminder = 2802

6 0
3 years ago
10 points.
rusak2 [61]

Answer:

<u>The difference between the experimental probability and the theoretical probability is 0.08 (rounding the answer to the nearest hundredth) or 8%.</u>

Correct statement and question:

Regina has a bag of 6 orange marbles and 6 black marbles. She picks a marble at random and then puts it back in the bag. She does this 24 times. The results can be found in the table.

Outcome Tally

Orange  10

Black     14

Figure out the percent error of pulling a black marble in Regina’s experiment. Show your work and round the answer to the nearest hundredth.

Source:

Previous question that can be found at brainly

Step-by-step explanation:

1. Let's review the information provided to us to answer the question correctly:

Number of orange marbles = 6

Number of black marbles = 6

Number of times of the experiment = 24

Number of times the outcome was an orange marble = 10

Number of times the outcome was a black marble  = 14

2. Figure out the percent error of pulling a black marble in Regina’s experiment. Show your work and round the answer to the nearest hundredth.

The theoretical probability of pulling a black marble is 12/24 or 0.5, given that the number of orange and black marbles are equal and actually, the experimental probability is 14/24 or 0.5833.

We can't describe this difference as an "error". What happened here is that there is a difference between the experimental probability and the theoretical probability.

0.5833 - 0.5 = 0.0833 = 0.08 (rounding the answer to the nearest hundredth)

<u>The difference between the experimental probability and the theoretical probability is 0.08 (rounding the answer to the nearest hundredth) or 8%.</u>

5 0
3 years ago
Please help I need to turn this is 30 min.
Soloha48 [4]

Answer:

46 ft2

Step-by-step explanation:

esorry if it doesnt lph

8 0
3 years ago
Volume of Spheres
Oliga [24]
It’s simple. The volume of a sphere is V=4/3πr^3.. so you will convert the mm to m okay?? 10mm=1cm .. so do your conversion from here then when you get the radius then you will substitute it into the volume where r is the radius.. so for the first one l changed mm to cm so.. radius is 4cm then l substitute it into the formula so l got 270 after rounding it to the nearest tenth.. pi=22/7 bear in mind. So do the same for the other one
6 0
2 years ago
PLZ HELP ME! Whoever gets it right will be marked brainiest
Brut [27]

Answer:

Probability that Hannah only has to buy 3 or less boxes before getting a prize is 0.784

Step-by-step explanation:

Given, 40% of cereal boxes contain a prize

⇒probability of getting a prize on opening a box, P(A)=0.4

where A is the event of getting a prize on opening a cereal box

and probability of not getting a prize on opening a box, P(A')=1-P(A)=0.6

where A' is the event of not getting a prize on opening a cereal box

This problem needs to be divided into 3 situation:

  • Case 1, Where Hannah gets prize when she buys the first box:

Let K be the event of Hannah winning the prize on buying the first box.

⇒P(K)=P(A)=0.4

  • Case 2, Where Hannah gets prize when she buys the second box:

I<u>n this event Hannah should not get the prize in first box but should get the prize on buying the second box</u>

Let L be the event of Hannah winning the prize on buying the second box

So, P(L)=P(A')·P(A)

           =(0.6)·(0.4)

           =0.24

  • Case 3,Where Hannah gets prize when she buys the third box:

<u>In this event Hannah should not get the prize in first and second box but should get the prize on buying the third box</u>

Let L be the event of Hannah winning the prize on buying the third box

So, P(L)=P(A')·P(A')·P(A)

           =(0.6)·(0.6)·(0.4)

           =0.144

Let N be the event of Hannah winning the prize on buying 3 or less boxes before getting a prize

⇒N=K∪L∪M

Now, Required probability is P(N)=P(K∪L∪M)=P(K)+P(L)+P(M) [As events K,L and M are independent and disjoint events]

⇒P(N)=0.4+0.24+0.144

         =0.784

7 0
3 years ago
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