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3 years ago

RoundingRound each number to the nearest hundred7892472

Mathematics

2 answers:

Mkey [24]3 years ago

5 0

Answer:

7900 and 500

Step-by-step explanation: While rounding if the number by the digit next to the place value we are rounding to (the 10's place value while rounding to the nearest hundred for example) is greater than 5, then you round up, if not, round down

mixas84 [53]3 years ago

4 0

Answer:

7892 = 7900

472 = 500

Step-by-step explanation:

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Factories A, B and C produce computers. Factory A produces 4 times as manycomputers as factory C, and factory B produces 7 times

Elina [12.6K]

Answer:

The probability is $P(A') = 0.485$

Step-by-step explanation:

Let assume that the number of computer produced by factory C is k = 1

So From the question we are told that

The number produced by factory A is 4k = 4

The number produced by factory B is 7k = 7

The probability of defective computers from A is $P(A) = 0.04$

The probability of defective computers from B is $P(B) = 0.02$

The probability of defective computers from C is $P(C) = 0.03$

Now the probability of factory A producing a defective computer out of the 4 computers produced is

$P(a) = 4 * P(A)$

substituting values

$P(a) = 4 * 0.04$

$P(a) = 0.16$

The probability of factory B producing a defective computer out of the 7 computers produced is

$P(b) = 7 * P(B)$

substituting values

$P(b) = 7 * 0.02$

$P(b) = 0.14$

The probability of factory C producing a defective computer out of the 1 computer produced is

$P(c) = 1 * P(C)$

substituting values

$P(c) = 1 * 0.03$

$P(b) = 0.03$

So the probability that the a computer produced from the three factory will be defective is

$P(t) = P(a) + P(b) + P(c)$

substituting values

$P(t) = 0.16 + 0.14 + 0.03$

$P(t) = 0.33$

Now the probability that the defective computer is produced from factory A is

$P(A') = \frac{P(a)}{P(t)}$

$P(A') = \frac{ 0.16}{0.33}$

$P(A') = 0.485$

3 0

3 years ago

I need help solving this problem

guapka [62]

Answer:

- 5/13

Step-by-step explanation:

tans = 5/12 = height/base

Using Pythagoras, hypotenuse = √12² + 5² = 13

Therefore coss had to be 12/13

But since cos s < 0, cos s = - 12/13

Thus,

tanA = sinA/cosA

tanA cosA = sinA

(5/12)(- 12/13) = sinA

- 5/13 = sinA

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Guys please help i’m nearly on 23% and i need to get to 82%- giving brainlest

liberstina [14]

Add the numbers they equal 30 then u divide 30 by 2 since it’s an odd number and you get 15. so 15 is your answer

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3 years ago

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Express .05 as a fraction in similest form

Alja [10]

0.05 = 5% = 5/100

Simplify 5/100 and you get 1/20.

Hope this helps & good luck. :)

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What can be concluded about a sorting algorithm (such as insertion) that performs only adjacent interchanges??

Oksanka [162]

It is the most critical part in algorithm. This is to sort or arrange things or numbers in specific characteristics. This is to make things easier when you will be calculating and you can differentiate the results and your variable being considered in solving the problem.

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3 years ago

RoundingRound each number to the nearest hundred7892472​

RoundingRound each number to the nearest hundred7892472