Answer:
The answers are that a = -5 and b = 1
Step-by-step explanation:
In order to find A and B, we first need to find the equation of the line. We can do this by using two ordered pairs and the slope formula. For the purpose of this activity, I'l use (0, 5) and (-3, 11)
m(slope) = (y2 - y1)/(x2 - x1)
m = (11 - 5)/(-3 - 0)
m = 6/-3
m = -2
Now that we have this we can model this using point-slope form.
y - y1 = m(x - x1)
y - 5 = -2(x - 0)
y - 5 = -2x
y = -2x + 5
Now that we have the modeled equation we can use the ordered pair (a, 15) to solve for a.
y = -2x + 5
15 = -2(a) + 5
10 = -2a
-5 = a
And we can also solve for b using the ordered pair (2, b)
y = -2x + 5
b = -2(2) + 5
b = -4 + 5
b = 1
I love blueberries so 10+y is not right answer
Answer:
let's see what to do buddy...
Step-by-step explanation:
Multiply the sides of the equation by 799
So A jar of the chemical contains 141 grams of <em><u>zinc</u></em>.
And we're done.
Thanks for watching buddy good luck.
♥️♥️♥️♥️♥️
Answer:
Cos(2115°) =1/√2
Sin(2115°) = -1/√2
Step-by-step explanation:
We have to find the values of Cos (2115°) and Sin (2115°).
Now, 2115° can be written as (23×90°+ 45°).
Therefore, the angle 2115° lies in the 4th quadrant where Cos values are positive and Sin values are negative.
Hence, Cos (2115°) = Cos(23×90° +45°) =Sin 45° {Since 23 is an odd number, so the CosФ sign will be changed to SinФ} =1/√2 (Answer)
Again, Sin (2115°) = Sin(23×90° +45°) = -Cos 45° {Since 23 is an odd number, so the SinФ sign will be changed to CosФ} = -1/√2 (Answer)
Now, the required reference angle is 45°. (Answer)
Answer:
The correct options are: Interquartile ranges are not significantly impacted by outliers. Lower and upper quartiles are needed to find the interquartile range. The data values should be listed in order before trying to find the interquartile range. The option Subtract the lowest and highest values to find the interquartile range is incorrect because the difference between lowest and highest values will give us range. The option A small interquartile range means the data is spread far away from the median is incorrect because a small interquartile means data is nor spread far away from the median
