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amid [387]
2 years ago
12

Write down in terms of n, an expression for the nth term

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
7 0

Answer:

In bold below.

Step-by-step explanation:

a)  Arithmetic sequence with common difference 3 and first term = 2:

nth term =  2 + 3(n - 1)

= 3n -1.

b)  Similar to above with common difference 2 and first term = 9.

nth term = 9 + 2(n - 1)

= 2n + 7.

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Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!
Anna71 [15]

Answer by JKismyhusbandbae: B) –10.6

Work/Explanation: Since the sequence slowly gets smaller, it is likely that each term is something added to (subtracted from) the previous term. To get from –7.9 to –8.8, it appears that the first has had –0.9 added to it. Continue adding –0.9 to get that the fourth term is –10.6.

8 0
3 years ago
Find the solution set
AVprozaik [17]
M1= -5 , m2 = 5 inorder to get this you move the constant to the right take the root of both sides separate the solutions and you should get m1= -5, m2 =5
7 0
3 years ago
Graph y = f(x) = 3(2)x. Adjust the equation to make the y-intercept (0, −3). Which response is not correct?
Sauron [17]

Answer:

Replace x with −x.

f(x) = 3(2)−x is not correct because the y-intercept is (0, 3).

the answer is B

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
at the school fair, of the people are under 16 years old. one-third of the people are teachers. if there are at least 21 one tea
Diano4ka-milaya [45]
Hello there!

Your correct answer will be 35 people under 16.

You know that 1/3 of the people are teachers, which means that 2/3 of people are left. Now, you need to get to the decimal value (.667). Make that number 1.667, because there will not be less teachers than students. Now, multiply:

1.667 x 21 = 35

There you go!
Brady
5 0
3 years ago
It costs $107 for 10 students and $137 for 15 students. How much does it cost for 12 students?
Anestetic [448]
\bf \begin{array}{ccccccccc}
&&\stackrel{students}{x_1}&&\stackrel{price}{y_1}&&\stackrel{students}{x_2}&&\stackrel{price}{y_2}\\
%  (a,b)
&&(~{{ 10}} &,&{{ 107}}~) 
%  (c,d)
&&(~{{ 15}} &,&{{ 137}}~)
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}\implies 
\cfrac{\stackrel{rise}{{{ y_2}}-{{ y_1}}}}{\stackrel{run}{{{ x_2}}-{{ x_1}}}}\implies \cfrac{137-107}{15-10}\implies \cfrac{30}{5}\implies \cfrac{6}{1}\implies 6

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-107=6(x-10)
\\\\\\
y-107=6x-60
\implies 
y=6x+47\\\\
-------------------------------\\\\
\textit{how much will it be for }\stackrel{x}{12~students?}\qquad y=6(12)+47
7 0
3 years ago
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