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Andrej [43]
3 years ago
10

Is (6, -4) a solution for the following system of equations?

Mathematics
1 answer:
irga5000 [103]3 years ago
7 0

Answer: no

Step-by-step explanation: explained in photo

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Alejandro looked at his first three science test for the quarter.His scores are represented i different ways
Darya [45]

Answer:Test one is 84% correct

Test two has a total of 20 questions

Test three he has 28 answers right


Step-by-step explanation:


5 0
3 years ago
Plz help becuase im trying to have this done in one min . ☝☝
In-s [12.5K]

Answer:

yes

Step-by-step explanation:

they both multiply by 20

4 0
3 years ago
Read 2 more answers
Please help me 4t−t+2
podryga [215]

Answer:

The answer is 3t + 2

Step-by-step explanation:

Subtract t from 4t.

hoped this helped!

brainly, please?

3 0
3 years ago
Identify the constant term in the function. y=−x2+3x−4
Oduvanchick [21]

constant term in any function is the term whose value does not change on variation of other parameters or in other case. We can also say constant term is independent of variable parameters.

take example

y = x + 3

here 3 is constant term which will not change either I change x or y . 3 is independent . it's just helps equation to hold information that overall in equation its matter.

so in given problem -4 is the constant

3 0
4 years ago
A jar contains 8 red marbles numbered 1 to 8 and 7 blue marbles numbered 1 to 7. A marble is drawn at random from the jar. Find
Shkiper50 [21]

Answer:

Therefore the probability that the marble is blue or even numbered is \frac{11}{15}

Step-by-step explanation:

Probability: The ratio of favorable outcomes to the total outcomes.

It is denoted by P.

Probability= \frac{\textrm{favorable outcomes}}{\textrm{Total outcomes}}

Given that a jar contains 8 red marbles and 7 blue marbles.

Total number of marbles = (8+7) = 15

Let A = Event of getting a blue marble

B= Event of getting of even marble.

Even number blue marbles are 2, 4,6

Even number red marbles are 2, 4,6,8

The number of even marbles are =(3+4)=7

The probability of getting a blue marble is P(A)

=\frac{\textrm{Total number of blue marbles}}{\textrm{Total number of blue marbles}}

=\frac{7}{15}

The probability of getting a even marble  is P(B)

=\frac{\textrm{The number of even number marbles}}{\textrm{Total number of marbles}}

=\frac{7}{15}

The probability of getting a even numbered blue marble P(A∩B)

=\frac{3}{16}

P(blue marble or even- numbered)

=P(A∪B)

=P(A)+P(B)-P(A∩B)

=\frac{7}{15} +\frac{7}{15}-\frac{3}{15}

=\frac{11}{15}

Therefore the probability that the marble is blue or even numbered is \frac{11}{15}

3 0
4 years ago
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