I'd suggest you sketch this situation. If you did, you'd likely see right away that the shortest distance back to the starting point would be the hypotenuse of the right triangle whose legs are of lengths 5 miles and 12 miles.

Apply the Pythagorean Theorem to solve this.

4 0

3 years ago

Find p(-4) and p(2) for the function p(x)=11x^5-11x^4-5x^2+15x-8

egoroff_w [7]

hi,

you must replace x by the number between parenthese.

I show you with the first one and let you do the second one

p(x) = 11x^5 -11x^4 - 5x^2 +15x-8

p(-4) = 11 (-4)^5 - 11 (-4)^4 -5(-4)² +15(-4) -8

p(-4) = 11 ( -1024- 256) - 5*16 -60-8

p(-4) = 11 ( -1280) -80-60-8

p(-4) = - 14080 - 148

p(-4) = - 14 228

7 0

2 years ago

What is the equation of the following line written in general form? (The y-intercept is -1.)

Strike441 [17]

2x-y-1=0

There are 2 ways that you can solve this . Either plug in the x and y value into each equation until it is right or rewrite the equation .
the equation in slope intercept form is y=2x-1
When you get y by itself in the last one it is also equal to y=2x-1
For both ways work is attached !

5 0

1 year ago

Calculate the annual return percentage

const2013 [10]

The annual returns will be calculated as follows:
a] Here we use the formula:
A=p(1+r/100)^n
A=future amount
p=principle
r=returns
n=time
We are given:
A=500, p=400, t=1
Plugging the values in the formula we obtain:
500=400(1+r)^1
simplifying and solving for r:
1.25=1+r
thus
r=1.25-1
r=0.25~25%

b] Using the formula above:
A=p(1+r/100)^n
A=2500+100=2600, p=2000, n=1 year
plugging the values in the equation we obtain:
2600=2000(1+r)^1
simplifying and solving for r we obtain:
2600/2000=1+r
1.3=1+r
hence
r=1.3-1
r=0.3~30%

7 0

3 years ago