Ask question

Ask question

All categories

riadik2000 [5.3K]

3 years ago

8

Simplify: 8x3 – 2x2 + x + 3x3 need answer asap

1 answer:

Black_prince [1.1K]3 years ago

7 0

The answer is 29 + x only.

You might be interested in

What is 18/25 as a decimal

Serga [27]

Answer: 0.72

Step-by-step explanation:

Hope that helps :)

4 0

3 years ago

Read 2 more answers

How to wirte a linear equation from a graph

astra-53 [7]

Hey there!
I'll assume we're using the slope-intercept form equation:
y = mx + b
m = slope
b = y-intercept
First, we keep the y, because it's value depends on the x value given.
Next, we find the slope. Slope is defined as rise/run, so we take two points on the graph, find how much taller one is from another, and how far right/left they are, put those values over each other, and we have out slope (m).
Finally, we need to determine the y-intercept, and that's as simple as seeing where the line crosses the y axis and writing down that value.
Hope this helps!

8 0

3 years ago

What is the equation of the graph below?On a coordinate plane, a curve crosses the y-axis at (0, negative 1). It has a minimum o

zzz [600]

ANSWER:

4th option: y = cosine (x + pi)

STEP-BY-STEP EXPLANATION:

For the function y = cosine (x), when x = 0, y = 1 and when x = , y = -1. The graph shows the opposite, when x = 0, y = -1 and when x = , y = 1, so we must add the same amount x = , for y to be positive 1.

So the equation of the graph would be:

$y=\cos(x+)$

The correct answer is then the 4th option y = cosine (x + pi)

3 0

11 months ago

Use the image below to answer the following question. Find the values of sin x°, cos x°, tan x°, sin y°, cos y°, and tan y°.

Molodets [167]

Answer:

the answer XxXxXxXxXx -YyYYYYY

Step-by-step explanation:

3 0

3 years ago

I need to use multi-step inverses with logs:

lubasha [3.4K]

Answer:

$f^{-1}(x)= \:\log _7\left(\left(8x-1\right)^3\right)$

Explanation:

$f(x) = \frac{(7^x)^{\frac{1}{3} }+1}{8}$

Let f(x) be y

$y = \frac{(7^x)^{\frac{1}{3} }+1}{8}$

exchange x and y

$x = \frac{(7^y)^{\frac{1}{3} }+1}{8}$

simplify

$8x= {(7^y)^{\frac{1}{3} }+1}$

simplify

$8x - 1 = 7^{\frac{y}{3} }$

simplify

$8x - 1 = \sqrt[3]{7^y}$

simplify

$(8x-1)^3 = 7^y$

apply log rules

$y = \frac{log((8x-1)^3 )}{log(7)}$

$y = \:\log _7\left(\left(8x-1\right)^3\right)$

therefore

$f^{-1}(x)= \:\log _7\left(\left(8x-1\right)^3\right)$

3 0

2 years ago