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riadik2000 [5.3K]
3 years ago
8

Simplify: 8x3 – 2x2 + x + 3x3 need answer asap

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
7 0
The answer is 29 + x only.
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Subtract. 44.3 – 2.74 = ?
larisa86 [58]
Your answer would be 41.56x
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What is 1.2+d+0.4=9.7?
Cloud [144]
1.2 + d + 0.4 = 9.7

1.6 + d = 9.7

1.6 (-1.6) + d = 9.7 (-1.6)

d = 8.1

your answer is 8.1

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Two lines intersect creating angles with the measures shown below.
Basile [38]

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  2x + 6 = 32

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7 0
3 years ago
Given vectors u = (−1, 2, 3) and v = (3, 4, 2) in R 3 , consider the linear span: Span{u, v} := {αu + βv: α, β ∈ R}. Are the vec
julia-pushkina [17]

Answer:

(2,6,6) \not \in \text{Span}(u,v)

(-9,-2,5)\in \text{Span}(u,v)

Step-by-step explanation:

Let b=(b_1,b_2,b_3) \in \mathbb{R}^3. We have that b\in \text{Span}\{u,v\} if and only if we can find scalars \alpha,\beta \in \mathbb{R} such that \alpha u + \beta v = b. This can be translated to the following equations:

1. -\alpha + 3 \beta = b_1

2.2\alpha+4 \beta = b_2

3. 3 \alpha +2 \beta = b_3

Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for \alpha,\beta and check if the third equationd is fulfilled.

Case (2,6,6)

Using equations 1 and 2 we get

-\alpha + 3 \beta = 2

2\alpha+4 \beta = 6

whose unique solutions are \alpha =1 = \beta, but note that for this values, the third equation doesn't hold (3+2 = 5 \neq 6). So this vector is not in the generated space of u and v.

Case (-9,-2,5)

Using equations 1 and 2 we get

-\alpha + 3 \beta = -9

2\alpha+4 \beta = -2

whose unique solutions are \alpha=3, \beta=-2. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.

4 0
3 years ago
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