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Tresset [83]
3 years ago
8

Question 3 of 10

Mathematics
1 answer:
Y_Kistochka [10]3 years ago
5 0
I think it’s B........
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1-69.
timofeeve [1]

The question above was not written properly

Complete Question

Lacey and Haley are rewriting expressions in an equivalent, simpler form.

a. Haley simplified x³⋅ x² and got

x⁵

Lacey simplified x³ + x² and got the same result! However, their teacher told them that only one simplification is correct. Who simplified correctly and how do you know?

b. Haley simplifies 3⁵⋅ 4⁵ and gets the result 12^10, but Lacey is not sure.

Is Haley correct? Be sure to justify your answer.

Answer:

a) Haley is correct, Lacey simplified wrongly.

b) Haley is incorrect

Step-by-step explanation:

a. Haley simplified x³⋅ x² and got

x⁵

Lacey simplified x³ + x² and got the same result! However, their teacher told them that only one simplification is correct. Who simplified correctly and how do you know?

For Question a, when it comes to simplifying algebraic expression that has to do with powers, there are certain rules that should be followed.

For example

x^a × x^b = x^(a + b)

For Haley, she simplified x³⋅ x² and got

x⁵

She is correct because this follows the product rule of powers or exponents above

= x³⋅ x² = x³+² = x⁵

For Lacey she is wrong because:

x³ + x² ≠ x⁵

x³ + x² when simplified as quadratic equation = x²(x + 1)

b. Haley simplifies 3⁵⋅ 4⁵ and gets the result 12^10, but Lacey is not sure.

Is Haley correct? Be sure to justify your answer.

For question b, when we have two distinct or different numbers with the same power(exponents) the rule states that:

x^a × y^a = (x × y)^a = (xy)^a

Haley is simplified wrongly. She did not apply the rule above

Haley simplified 3⁵⋅ 4⁵ = (3 × 4) ⁵+⁵

= 12^10, this is wrong.

The correct answer according to the rule =

3⁵⋅ 4⁵ = (3 × 4) ⁵ = 12⁵

Therefore,

3⁵⋅ 4⁵ ≠ 12^10

3⁵⋅ 4⁵ = 12⁵

Haley is wrong.

3 0
3 years ago
Y
choli [55]

Answer:

where is the figure????

4 0
3 years ago
Consider the universal set R,R, define the interval A=[−7,1],A=[−7,1], interval B=(−1,5),B=(−1,5), and CC be the negative real n
AURORKA [14]
Draw a diagram representing the real number line, and the sets A  and B.

According to the diagram:

<span>1. A∪B= [-7, 5)

2. </span><span>2. A∩B∩C= (-1, 0)

</span>3. A∩(B∪C)= [-7, 1] <span>∩ (-INFINITY, 5) = [-7, 1]

4. </span>4. A^c ∪ B^c∪ C^c= (not A) ∪ (not B) ∪ (not C) = 

(-infinity, -7) ∪ (1, infinity)   ∪  (-infinity, -1] ∪ [5, infinity)   ∪ [0, infinity)

= (-infinity, -1] ∪ (1, infinity ) ∪ [0, infinity) = (-infinity, -1] ∪ [0, infinity) 

5. (C−A)∪(B−C)= "in C but not in A" union "in B but not in C"

=(-infinity, -7) ∪ [0, 5) 

8 0
3 years ago
5 times a number, subtracted from six, is triple the number
Kryger [21]
5x -6 = 3x would be this word problem in equation form
8 0
3 years ago
Which one of the following statements is FALSE?
adell [148]

Answer:

D

Step-by-step explanation:

3 0
3 years ago
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