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faltersainse [42]
4 years ago
9

Working together, it takes Sam, Jenna, and Francisco two hours to paint one room. When Sam works alone, he can paint one room in

6 hours. When Jenna works alone, she can paint one room in 4 hours. Determine how long it would take Francisco to paint one room on his own.
Mathematics
1 answer:
lutik1710 [3]4 years ago
8 0

Answer:  12 hours

Step-by-step explanation:

Given : Working together, it takes Sam, Jenna, and Francisco two hours to paint one room.

When Sam works alone, he can paint one room in 6 hours. When Jenna works alone, she can paint one room in 4 hours.

Let 't' be the time taken by Francisco to paint one room on his own.

Then , we have

Rate of work of  Sam +Rate of work of Jenna + Rate of work of  Francisco =Rate of work they all do together

\dfrac{1}{6}+\dfrac{1}{4}+\dfrac{1}{t}=\dfrac{1}{2}

i.e.  \dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{1}{6}+\dfrac{1}{4})

i.e.  \dfrac{1}{t}=\dfrac{1}{2}-(\dfrac{4+6}{24})

i.e.  \dfrac{1}{t}=\dfrac{1}{2}-\dfrac{10}{24}

i.e.  \dfrac{1}{t}=\dfrac{1}{2}-\dfrac{5}{12}

i.e.  \dfrac{1}{t}=\dfrac{6-5}{12}

i.e.  \dfrac{1}{t}=\dfrac{1}{12}

i.e. t= 12

Hence,  Francisco would take 12 hours to  paint one room on his own.

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Answer:

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Step-by-step explanation:

Because they are winning 57.14% of there games so if 8 out of 14=57.14% then that means if they would have still one at the exact pace then.

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Hope this helps have a great afternoon:)

4 0
3 years ago
In isosceles triangle ABC, AB=AC.If B=55, calculate A​
den301095 [7]

Answer: ∠A = 70°

because ABC is an  isosceles triangle and AB =  AC

=> ∠B = ∠C = 55°

=> ∠A = 180-(∠B + ∠C) = 180° - 55°.2 = 70°

Step-by-step explanation:

4 0
3 years ago
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sertanlavr [38]

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Step-by-step explanation:

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Find the area of each figure . Round to nearst tenth if necessary
garri49 [273]
The area of the trapezoid :
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