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sashaice [31]
2 years ago
15

Evaluate –10 • x • 5 when x = –1. –50 –15 6 50

Mathematics
1 answer:
Rudiy272 years ago
4 0
The answer is 50 ! :-)
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s2008m [1.1K]

Answer:

This is the answer. All the very best. Do it

6 0
3 years ago
What is /-3/*-6?<br><br> When you answer could you please explain to me why the answer is that?
jekas [21]
|-3|=3 right?
Then it is
3*-6=-18
8 0
3 years ago
PLEASE Answer! I'll Give Brainliest And A Thanks For A GOOD Answer.
melisa1 [442]

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5 0
3 years ago
(x-2)^3+13=-112<br> <img src="https://tex.z-dn.net/?f=%28x-2%29%5E3%2B13%3D-112" id="TexFormula1" title="(x-2)^3+13=-112" alt="(
yKpoI14uk [10]

Answer:

x = -3

Step-by-step explanation:

(x - 2)^3 + 13 = -112

Subtract 13 from both sides

(x - 2)^3  = -125

Take the cube root of both sides

x - 2 = -5

Add 2 to both sides

x = -3

7 0
3 years ago
Part A
olasank [31]
<h3>Answer:</h3>
  • B. f(x) = 3,000(0.85)^x
  • $1566.02
<h3>Step-by-step explanation:</h3>

Part A

At the end of the year, the value of the computer system is ...

... (beginning value) - 15% · (beginning value) = (beginning value) · (1 - 0.15)

... = 0.85 · (beginning value)

Since the same is true for the next year and the next, the multiplier after x years will be 0.85^x. Then the value after x years is ...

... f(x) = (beginning value) · 0.85^x

The beginning value is given as $3000, so this is ...

... f(x) = 3000·0.85^x

____

Part B

For x=4, this is ...

... f(4) = 3000·0.85^4 = 3000·0.52200625 ≈ 1566.02

The value after 4 years is $1566.02.

8 0
3 years ago
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