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zhannawk [14.2K]
2 years ago
11

Https://smart.newrow.com/room/nr2/?room_id=ihe-281&firstRun

Mathematics
2 answers:
oee [108]2 years ago
7 0

Answer:

i'll be there and if anyone cares to join please do

Step-by-step explanation:

Dahasolnce [82]2 years ago
3 0

Answer:

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤-❤-❤-

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What is the solution set?<br> O (0-2)<br> O (2.0)<br> O (7,0)<br> O (5,3)
muminat

Answer:

D. (5,3)

Step-by-step explanation:

The solution is (x,y). so in this case, you find the point where both arrows meet.

on the x-axis, which is positive right 5, and positive 3 up, on the y-axis

3 0
2 years ago
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Which table represents a function with a slope of 1/2 and a y-intercept of 4
Volgvan

Answer:D

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8 0
2 years ago
Twice the difference of a number and 3 is 5.​
Xelga [282]

Answer:

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Step-by-step explanation:

7 0
2 years ago
Suppose yoko borrows $3500 at an interest rate of 4% compounded each year Find the amount owed at the end of 1 year
olchik [2.2K]

Amount owed at the end of 1 year is 3640

<h3><u>Solution:</u></h3>

Given that yoko borrows $3500.

Rate of interest charged is 4% compounded each year

Need to determine amount owed at the end of 1 year.

In our case :

Borrowed Amount that is principal P = $3500

Rate of interest r = 4%

Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1

<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

A=p\left(1+\frac{r}{100}\right)^{n}

Where "p" is the principal

"r" is the rate of interest

"n" is the number of years

Substituting the values in above formula we get

\mathrm{A}=3500\left(1+\frac{4}{100}\right)^{1}

\begin{array}{l}{A=\frac{3500 \times 104}{100}} \\\\ {A=35 \times 104} \\\\ {A=3640}\end{array}

Hence amount owed at the end of 1 year is 3640

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3 years ago
Solve for x. Round to the nearest tenth, if necessary.<br> S<br> 9<br> х<br> Q<br> 75°<br> R
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Sine 75 = x/ 9
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