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zhannawk [14.2K]
3 years ago
11

Https://smart.newrow.com/room/nr2/?room_id=ihe-281&firstRun

Mathematics
2 answers:
oee [108]3 years ago
7 0

Answer:

i'll be there and if anyone cares to join please do

Step-by-step explanation:

Dahasolnce [82]3 years ago
3 0

Answer:

❤❤❤❤❤❤❤❤❤❤❤❤❤❤❤-❤-❤-

You might be interested in
Which of the following scenarios could be represented by the expression
wolverine [178]

Answer:

Step-by-step explanation:

I am going with A......12x + 7y....x = # of adult and y = # of children.....adults cost 12 and children cost 7 <====

B doesn't make much sense....u could say x was for girls and y for boys...but u already know how many there are....so I am not sure what the x and y could stand for.

C does't make much sense either....x would have to be red marbles and y would have to be green marbles...but just like B, u already know how many there are....so not sure what x and y could stand for

D. wrong....because the box containing x 7 oz packages and y 12 oz packages.....12x + 7y....for this one to be correct, it would have to have x 12 oz packages and y 7 oz packages

7 0
3 years ago
Sarah described the following situation:
olganol [36]

Answer:

I believe the answer is B.

Step-by-step explanation:

4 0
4 years ago
HELPS PLEASE! WILL GET ALL MY POINTS
liberstina [14]
Your answer would be 22 watermelons.

We can find this by adding together the quantity of watermelons for each weight, so:

1 + 7 + 10 + 4 = 22

I hope this helps!
4 0
4 years ago
Read 2 more answers
Can anyone help me out ?
svlad2 [7]

Answer:

what is your question.. if any problems then I will try to solve if I know.

4 0
3 years ago
Three couples go to the movie theater. They want to seat people together for maximum enjoyment, but instead they randomly file i
Marat540 [252]

As there are 3 couples, so that means there are total 3 × 2 = 6 people altogether.

So now to make 6 people sit on 6 sits can be done in folowing ways:

suppose these are 6 seats available

_____1__ ______2___ ____3______ ___4__ ____5___ ___6____

Now there are 6 ways to make a person sit on seat 1.

Once seat 1 is occupied we are left with 5 people (1 person sat on seat 1)

so now 2nd seat can be filled in 5 ways

after 1 person sat on seat 2, then 3rd seat can be filled in 4 ways ( out of 6 people already 2 people sat on seat 1 and 2 so only 4 people left for 3rd seat)

And similarly for 4th seat can be filled in 3 ways

then 5th seat can be filled in 5 ways

then 6th seat can be filled in only 1 way.

Now as per fundamental principle of counting if there are m ways to do one event and n ways to do another event so altogether are m × n ways to do them.

So using same fundamental principle of counting here we get total ways to make 6 people sit on 6 seats as 6 × 5 × 4 × 3 × 2 × 1 or 6! = 720 ------------(1)

----------------------------------------------------------------------------------------------------

Now they want each couple to sit together. So every two particular people make one group (1 couple).

so like we saw 6 people can be seated on 6 seats in 6! ways (from (1))

similarly 3 couples can be seated in 3! or 3 × 2 × 1 = 6 ways

And 1st couple can sit in 2 ways amoung themselves (husband left wife right or wife left and husband right).

similarly 2nd couple can also sit in 2 ways amoung themselves

and 3rd couple can also sit in 2 ways amoung themselves

So altogether, by funadmental principle of counting, all 3 couples can be seated in 6 × 2 × 2 × 2 = 48 ways -----------(2)

--------------------------------------------------------------------------------------------

Probability of event is given by formula:

Probability = \frac{Number- of- favourable-outcomes}{Total-number-of -outcomes}

so favourable outcomes from (2) we have as 48

total number of outcomes from (1) we have 720.

so plug these value in probability formula

Probability = \frac{48}{720}

To reduce this fraction divide by greatest common factor in 48 and 720 which is 48. so we get

\frac{48 \div 48}{720 \ div 48} = \frac{1}{15}

so thats the final answer.

8 0
3 years ago
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