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3 years ago

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At the local dairy farm, Kareem buys a 32-oz container of yogurt for $2.56. Jonah buys a 6-oz container of yogurt for $0.48. Are

the cost, y, in dollars and the amount of yogurt, x, proportional? Explain. Write an equation to represent this relationship.
BRAINLIEST IF ANSWER

1 answer:

sertanlavr [38]3 years ago

3 0

Here u go, hope this helps

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Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

<u>Ben:</u>

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

<u>Josh:</u>

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

<em><u>Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at </u></em> $h(t)=0$ <em><u>. Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one. </u></em>

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$

Since time can only be positive we reject the $t_{2}$ solution and we keep that Ben's book took $t=4.3276$ seconds to reach the ground.

Similarly solving for Josh we obtain

$t_{1}=3.6794sec\\t_{2}=-0.6794sec$

Thus again we reject the negative and keep the positive solution, so Josh's book took $t=3.6794$ seconds to reach the ground.

Then we can find the difference between Ben and Josh times as

$t_{Ben}-t_{Josh}= 4.3276 - 3.6794 = 0.6482$

So to answer the original question:

<em>Whose textbook reaches the ground first and by how many seconds?</em>

Josh's textbook reached the ground first
Josh's textbook reached the ground first by a difference of $t=0.6482$

3 0

3 years ago

What is 65,759.59 rounded to the nearest tenth

coldgirl [10]

65,759.60

Hope this helps

6 0

3 years ago

Pemdas, thank you! <br>(-8 × -6) -4²

Aleksandr-060686 [28]

Answer:

32

Step-by-step explanation:

(-8 × -6) - 4²

48 - 4²

48 - 16 = 32

P - Parentheses

E - Exponents

M - Multiplication

D - Division

A - Addition

S - Subtraction

8 0

2 years ago

Read 2 more answers

William is reading a book for class . The book is 94 pages long . For the first assignment , William read 25 pages . For the sec

rjkz [21]

The answer is 32, I hope this helps!!

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2 years ago

Triangle m is similar to triangle n. Triangle m has two angles with measures of 32°and 93°. Which two angles measures could be i

inysia [295]

Given that triangle m and n are similar, then the implication is the ratio of the corresponding sides are the same and the corresponding angles are equal. This implies that if the two angles of triangle m measure 32° and 93°, then the possible size for the two angles in triangle n will be 32° and 93°.

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3 years ago