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2 years ago

Help answer helpppp ASAP this TIMED.

Mathematics

1 answer:

eduard2 years ago

6 0

Answer:

57/8 or 7 1/8

Step-by-step explanation:

I think that you would find how many times it fits in the graph which I found it fit three times so you would multiply th e length by three.

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A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

Find the cos A and tan B to four decimal places. URGENT

Nikolay [14]

cos A is 0.8511 and tan B is 1.6

Step-by-step explanation:

Find the 3rd length or the hypotenuse.

Pythagoras theorem

$hypotenuse^{2}$ = $adjacent^{2}$ + $opposite^{2}$

$hypotenuse^{2}$ = $8^{2}$ + $5^{2}$

$hypotenuse^{2}$ = 64 + 25

hypotenuse = $\sqrt{89}$

hypotenuse = 9.4

a) Cos A

Data:

Adjacent = 8

Hypotenuse = 9.4

Formula:

Cos (Angle) = $\frac{adjacent}{hypotenuse}$

Cos A = $\frac{8}{9.4}$

Cos A = 0.8511

A = $cos^{-1}$ (0.8511)

A = 31.7°

b) Tan B

Data:

Opposite = 8

Adjacent = 5

Formula:

Tan (Angle) = $\frac{opposite}{adjacent}$

Tan B = $\frac{8}{5}$

Tan B = 1.6

B = $cos^{-1}$ (1.6)

B = 58°

Therefore, cos A is 0.8511 and tan B is 1.6.

Keyword: cos, tan

Learn more about cos at

#LearnwithBrainly

3 0

3 years ago

Newberg has a population of 31,000 people. The town has been seeing its population decline by 10% every year. If this trend cont

valentina_108 [34]

Answer:

13,000

Step-by-step explanation: 10% of 31,000= 3,100 x 6= 18,600

31,000-18,600=13,000

4 0

3 years ago

3,400,000 34,000 is that right

mart [117]

Yes that is right all the numbers are in the right place value in the decimals are in the right place value

8 0

3 years ago

Read 2 more answers

Tien reads for 45 minutes each night before going to bed. Which expression will

Svetllana [295]

Answer:

135 !!!!!!!!!!!!

Step-by-step explanation:

Your welcome!!!

8 0

3 years ago