Is that one or two questions?
Answer:
There is no solution for this set of equations.
The sum of two numbers can not have two different solutions.
Answer:
The length of the rectangle 'l' = 20
The width of the rectangle 'w' = 14
Step-by-step explanation:
<u>Explanation</u>:-
Let 'x' be the width
Given data the length of a rectangular patio is 8 feet less than twice its width
2x-8 = length
The area of rectangle = length X width
Given area of rectangle = 280 square feet
x(2x-8) = 280
2(x)(x-4) =280
x(x-4) =140
x^2 -4x -140=0
x^2-14x+10x-140=0
x(x-14)+10(x-14)=0
(x+10)(x-14) =0
x = -10 and x = 14
we can choose only x =14
The width of the rectangle 14
The length of the rectangle 2x-8 = 2(14)-8 = 28 -8 =20
The length of the rectangle 'l' = 20
The width of the rectangle 'w' = 14
Answer:
I believe the answer is a=58
Step-by-step explanation:
a=1+25+8+24
a=26+8+24
a=34+24
a=58
