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Tcecarenko [31]
2 years ago
12

Please help me with the work please help

Mathematics
1 answer:
alekssr [168]2 years ago
4 0
Im not sure how to help but search up "module [-] lesson [-] grade [-]" ! then click thr first link, it should be engageny, once u click that link, scroll down until u see something like - pdf grade [-] mathematics stuff - make sure to press the teacher ver !
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Which of the following is a unit rate?
Snezhnost [94]

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The third option (foot/1 hour)

Step-by-step explanation:

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Please help if you think you hot beautiful kind funny cool please help me please
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Answer/Step-by-step explanation:

The equation of the line that passes through the two points would be correct if each point, when substituted into the equation, satisfy the equation.

This is what I mean:

Given the equation of the line, y = 2x - 5, and the two points (-2, -9) and (3, 1):

For the first point, substitute x = -2, and y = -9 into y = 2x - 5.

Thus:

-9 = 2(-2) - 5

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For the second point, substitute x = 3, and y = 1 into y = 2x - 5

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1 = 1 (this is true). This also means the point, (3, 1) is also a point that the equation runs across.

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2 years ago
Suppose that X is a subset of Y. Let p be the proposition ‘x is an element ofX’ and let q be the proposition ‘x is an element of
Genrish500 [490]

Answer:

See answer below

Step-by-step explanation:

The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.

i) x∈AnB  if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB  then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.

ii) (I will abbreviate "if and only if" as "iff")

x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.

iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).

iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).

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why

Step-by-step explanation:

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HELP ME !?!!!!?!?? Please
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Step-by-step explanation:i havent done something like this in a long time

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