Answer:
The third option (foot/1 hour)
Step-by-step explanation:
Answer/Step-by-step explanation:
The equation of the line that passes through the two points would be correct if each point, when substituted into the equation, satisfy the equation.
This is what I mean:
Given the equation of the line, y = 2x - 5, and the two points (-2, -9) and (3, 1):
For the first point, substitute x = -2, and y = -9 into y = 2x - 5.
Thus:
-9 = 2(-2) - 5
-9 = -4 - 5
-9 = -9 (this is true). It means the line runs through the point (-2, -9)
For the second point, substitute x = 3, and y = 1 into y = 2x - 5
This:
1 = 2(3) - 5
1 = 6 - 5
1 = 1 (this is true). This also means the point, (3, 1) is also a point that the equation runs across.
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
Answer:
Step-by-step explanation:i havent done something like this in a long time
