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3 years ago

Help I will give you 10 points please help

Mathematics

1 answer:

maxonik [38]3 years ago

7 0

Answer:

Look Below

Step-by-step explanation:

1. A person would have to work 9 Hours to get 63$ for 7$ per hour.

2. Reese is 16 years old because if you do 34 - 18 = 16. Or you could do 16 + 18 = 34 to confirm it.

3. 10 - 4 = 6 Sean is 6 feet tall total because if you do a subtraction problem with the two variables you get 6.

4. I am not able to see the numbers on the right unfortunately so all you have to do for this one is to minus how much her brother has by 8 to get her amount.

Hope This Helps! Have A Good Day! Good Luck With Your Work!

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I will upvote and give brainliest answer

Citrus2011 [14]

Answer:

x = 58 degrees

Step-by-step explanation:

Angle K (which is x) and Angle I are congruent corresponding angles with one another, so if, as an example, Angle I was 10, Angle K would also be 10.

All you need to do in this case is add Angle H (56) and Angle A (66) together:

56 + 66 = 122

Then subtract 122 from 180 (because triangles add up to 180 degrees) to get x:

180 - 122 = 58

So, x = 58 degrees.

7 0

3 years ago

In a dance competition, a participant has to score a total of at least 30 points in the first four rounds combined to move on to

Anvisha [2.4K]

Answer:

5 + 3p ≥ 30

Step-by-step explanation:

"at least" means greater than are equal to. ≥

So we already know he has 5 points, but the other 3 rounds we don't. 5 + 3p

30 is the overall points he has.

5 + 3p ≥ 30

4 0

3 years ago

A company wants to find out if the average response time to a request differs across its two servers. Say µ1 is the true mean/ex

lorasvet [3.4K]

Answer:

a) The null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

Test statistic t=0.88

The P-value is obtained from a t-table, taking into acount the degrees of freedom (419) and the type of test (two-tailed).

b) A P-value close to 1 means that a sample result have a high probability to be obtained due to chance, given that the null hypothesis is true. It means that there is little evidence in favor of the alternative hypothesis.

c) The 95% confidence interval for the difference in the two servers population expectations is (-0.372, 0.972).

d) The consequences of the confidence interval containing 0 means that the hypothesis that there is no difference between the response time (d=0) is not a unprobable value for the true difference.

This relate to the previous conclusion as there is not enough evidence to support that there is significant difference between the response time, as the hypothesis that there is no difference is not an unusual value for the true difference.

Step-by-step explanation:

This is a hypothesis test for the difference between populations means.

The claim is that there is significant difference in the time response for the two servers.

Then, the null and alternative hypothesis are:

$H_0: \mu_1-\mu_2=0\\\\H_a:\mu_1-\mu_2\neq 0$

The significance level is 0.05.

The sample 1, of size n1=196 has a mean of 12.5 and a standard deviation of 3.

The sample 2, of size n2=225 has a mean of 12.2 and a standard deviation of 4.

The difference between sample means is Md=0.3.

$M_d=M_1-M_2=12.5-12.2=0.3$

The estimated standard error of the difference between means is computed using the formula:

$s_{M_d}=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma_2^2}{n_2}}=\sqrt{\dfrac{3^2}{196}+\dfrac{4^2}{225}}\\\\\\s_{M_d}=\sqrt{0.046+0.071}=\sqrt{0.117}=0.342$

Then, we can calculate the t-statistic as:

$t=\dfrac{M_d-(\mu_1-\mu_2)}{s_{M_d}}=\dfrac{0.3-0}{0.342}=\dfrac{0.3}{0.342}=0.88$

The degrees of freedom for this test are:

$df=n_1+n_2-1=196+225-2=419$

This test is a two-tailed test, with 419 degrees of freedom and t=0.88, so the P-value for this test is calculated as (using a t-table):

$\text{P-value}=2\cdot P(t>0.88)=0.381$

As the P-value (0.381) is greater than the significance level (0.05), the effect is not significant.

The null hypothesis failed to be rejected.

There is not enough evidence to support the claim that there is significant difference in the time response for the two servers.

Confidence interval

We have to calculate a 95% confidence interval for the difference between means.

The sample 1, of size n1=196 has a mean of 12.5 and a standard deviation of 3.

The sample 2, of size n2=225 has a mean of 12.2 and a standard deviation of 4.

The difference between sample means is Md=0.3.

The estimated standard error of the difference is s_Md=0.342.

The critical t-value for a 95% confidence interval and 419 degrees of freedom is t=1.966.

The margin of error (MOE) can be calculated as:

$MOE=t\cdot s_{M_d}=1.966 \cdot 0.342=0.672$

Then, the lower and upper bounds of the confidence interval are:

$LL=M_d-t \cdot s_{M_d} = 0.3-0.672=-0.372\\\\UL=M_d+t \cdot s_{M_d} = 0.3+0.672=0.972$

The 95% confidence interval for the difference in the two servers population expectations is (-0.372, 0.972).

7 0

3 years ago

Simplify the following expression. A. B. C. D.

Dahasolnce [82]

Answer:

Step-by-step explanation:

Let's start by crossing everything out!

12/3 can be crossed out to 4.

a^3/a^2 can be crossed out to a.

b^6/b^4 can be crossed out into b^2.

c^5/c^5 is just 1.

So which the results we got, we can multiply them, so that it is 4ab^2.

4ab^2 is our final answer!

5 0

2 years ago

Someone help please !!!!!

k0ka [10]

Answer:

Step-by-step explanation:

please mark as brain and like please please follow me and I'm waiting excitedly for the reaction of you and your like

4 0

2 years ago