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AVprozaik [17]
3 years ago
10

Simplify the expression below, I really just need the steps I have the answer (also can someone tell me how to edit points on th

e app)

Mathematics
1 answer:
Sloan [31]3 years ago
4 0

Answer:  3x^2y\sqrt[3]{y}\\\\

Work Shown:

\sqrt[3]{27x^{6}y^{4}}\\\\\sqrt[3]{3^3x^{3+3}y^{3+1}}\\\\\sqrt[3]{3^3x^{3}*x^{3}*y^{3}*y^{1}}\\\\\sqrt[3]{3^3x^{2*3}*y^{3}*y}\\\\\sqrt[3]{\left(3x^2y\right)^3*y}\\\\\sqrt[3]{\left(3x^2y\right)^3}*\sqrt[3]{y}\\\\3x^2y\sqrt[3]{y}\\\\

Explanation:

As the steps above show, the goal is to factor the expression under the root in terms of pulling out cubed terms. That way when we apply the cube root to them, the exponents cancel. We cannot factor the y term completely, so we have a bit of leftovers.

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               The coefficient (in green) will be 2.12

Step-by-step explanation:

     Scientific notation is written by multiplying the number by a power of 10. This number is a number between 1 and 10.

     Since this is a smaller number, we will be multiplying it by a power of 10 to a negative number.

    To get this value to a number between 1 and 10, we must multiply it by 10 3 times (also shown as 10³) which gives us 2.12.

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Question 12 (1 point)
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
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