No (random words to reach 20 characters lol)
For the first digit you are choosing from 2 digits
for the second digit you are choosing from 2 digits
for the third digit you are choosing from 2 digits
2*2*2=8
111
110
011
101
000
001
100
010
However......
A number doesn't usually start with a 0 or 0s.
Therefore, if you want 3-digit numbers and not just permutations using 0 and 1, then you must eliminate
011, 000, 001, and 010
Seeing that the first digit can't be 0, you choose from 1, then 2, and then 2 digits again; 1*2*2=4 numbers
You choose which answer best suits your problem.
Step-by-step explanation:
<em>2</em><em>+</em><em>1</em><em>9</em><em>=</em><em>7x</em>
<em>2</em><em>1</em><em>=</em><em>7x</em>
<em>21</em><em>÷</em><em>7</em><em>=</em><em>7x</em><em>÷</em><em>7</em>
<em>3</em><em>=</em><em>x</em>
<em>.</em><em>.</em>
The answer is 35,000
To get this I multiplied 7*5 first (35) then added three zeros because 1000 has three zeros.
Hope this helped :)