Alright, second part of Absolute Value Homework.. For part c i need a number line that looks like the one i have attached please
. Help is MUCH appreciated!!!
2 answers:
Answer:
a. -0.01 < x - 8 < 0.01
b. 7.99 < x < 8.01
c. see attachment
d. Bolt has to be greater than 7.99 mm and less than 8.01 mm to be within the margin of error of 0.01 mm.
Step-by-step explanation:
-0.01 < x - 8 < 0.01
-0.01 < x - 8 and x - 8 < 0.01
7.99 < x x < 8.01
Write this as: 7.99 < x < 8.01
On graph the 7.99 and 8.01 are very near to each other and represented via open red circle.
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Refer to the diagram shown below.
At an arbitrary point P (x,y) on the parabola, the distance, d, from the focus to P should be equal to the distance from P to the directrix.
That is,
d² = (x - 3)² + (y - 4)² = (y - 1)²
(x - 3)² + y² - 8y + 16 = y² - 2y + 1
(x - 3)² + 15 = 6y
Divide each side by 6 to obtain
y = (1/6) (x - 3)² + 5/2
The vertex of the parabola is at (3, 5/2).
The line of symmetry is x = 3.
The leading coefficient, 1/6, is positive, therefore the curve opens upward.
Answer:
At an arbitrary point P (x,y) on the parabola, the distance, d, from the focus to P should be equal to the distance from P to the directrix.
That is,
d² = (x - 3)² + (y - 4)² = (y - 1)²
(x - 3)² + y² - 8y + 16 = y² - 2y + 1
(x - 3)² + 15 = 6y
Divide each side by 6 to obtain
y = (1/6) (x - 3)² + 5/2
The vertex of the parabola is at (3, 5/2).
The line of symmetry is x = 3.
The leading coefficient, 1/6, is positive, therefore the curve opens upward.
Answer:
Answer:
hope it's help you
Solved By: Varun Rathore
