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3 years ago

Help me please I will mark brainly

Mathematics

2 answers:

vaieri [72.5K]3 years ago

5 0

Answer:

Step-by-step explanation:

Colt1911 [192]3 years ago

5 0

Answer:

A= -13/35

B= 13/35

C= -27/35

D= -13/35

The answer is B

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Pls Need Answer Now!!

iris [78.8K]

Answer:

Option B, 14.6 units

Step-by-step explanation:

Step 1: Find the distance of AB

$AB =$ $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$AB =$ $\sqrt{(3 - 1)^2 + (5 - 3)^2}$

$AB =$ $\sqrt{(2)^2 + (2)^2}$

$AB =$ $2\sqrt{2}$ or 2.83...

Step 2: Find the distance of BC

$BC =$ $\sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

$BC = \sqrt{(3 -1)^2 + (-1 - 3)^2}$

$BC = \sqrt{(2)^2 + (-4)^2}$

$BC = \sqrt{4 + 16}$

$BC = \sqrt{20}$

$BC = 2\sqrt{5}$ or 4.47...

Step 3: Find the perimeter

AB is the same as AD and BC is the same as DC

$2(AB) + 2(BC)$

$2(2.83) + 2(4.47)$

$5.66 + 8.94$

14.6 units

Answer: Option B, 14.6 units

5 0

3 years ago

Triangles A and B have vertical heights x cm and (x+3) cm respectively. The areas of Triangles A and B are 30cm² and 32cm² respe

PolarNik [594]

Answer:

Hi,

Step-by-step explanation:

Let say a the base of the triangle A and b the base of the triangle B.

$a)\\\left\{\begin{array}{ccc}\dfrac{a*x}{2}&=&30\\\dfrac{b*(x+3)}{2}&=&32\\b=a-4\\\end{arraqy}\right.\\\\(i): a=\dfrac{60}{x}\\\\(ii): b=\dfrac{64}{x+3}\\\\b)\\\dfrac{64}{x+3}=\dfrac{60}{x}-4\\\\64x=(60-4x)*(x+3)\\\\4x^2+16x-180=0\\\\x^2+4x-45=0\\\\\Delta=16+4*45=196=14^2\\x=\dfrac{-4+14}{2}=5\ or\ x=\dfrac{-4-14}{2}=-9\ (impossible)\\So\ x=5,\ a=\dfrac{60}{5}=12, b=\dfrac{64}{5+3}=8\\\\Area\ of\ A=12*5/2=30\\Area\ of\ B=8*8/2=32\\\\Height\ of\ triangle\ B=x+3=5+3=8.\\$