In the plane, we have everywhere. So in the equation of the sphere, we have
which is a circle centered at (2, -10, 0) of radius 4.
In the plane, we have , which gives
But any squared real quantity is positive, so there is no intersection between the sphere and this plane.
In the plane, , so
which is a circle centered at (0, -10, 3) of radius .
41/6-5/6 = 36/6
36/6= 6
So 5/6 would need to be subtracted to develop a fraction that divides to 6
Answer:
c.i^ 3
Step-by-step explanation:
i^7/i x i^3
i ^ 7 / i ^ 4
i^ 7 - 4
i^ 3