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3 years ago

Evaluate the expression. 20- 3^2 x 2

Mathematics

2 answers:

Gemiola [76]3 years ago

5 0

Answer: 2

Step-by-step explanation:

Remember PEMDAS!

20 - 3^2 x 2

20 - 9 x 2

20 - 18

hope this helps :)

Zigmanuir [339]3 years ago

3 0

Answer:

Step-by-step explanation:

20 - 3^2 • 2

20 - 9 • 2

20 - 18

Hope this helps, good luck! :)

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Hannah is saving for a trip during the upcoming summer break. She recorded the total amount of money she had in her trip account

EleoNora [17]

D) is correct.

Looking at the graph, it goes through the point (2, 200) and is very near the point (3, 300). This means it increases by nearly 100 every month; this tells us how much she saves each month.

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3 years ago

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katen-ka-za [31]

Answer:

750 < p < 1500

Step-by-step explanation:

The total cost of the affair for p attendees is ...

750 +2.25p

The average cost is that number divided by p. The answer choices suggest that "between" means that the cost per person cannot be 2.75 or 3.25. Applying the limits to the average cost, we get ...

2.75 < (750 +2.25p)/p < 3.25

2.75 < 750/p + 2.25 < 3.25 . . . . . . . . separating the fraction parts

0.50 < 750/p < 1.00 . . . . . . . . . . . . . . subtract 2.25

2 > p/750 > 1 . . . . . . . . . . . . . . . . . . . . . take the reciprocal*

1500 > p > 750 . . . . . . . . matches choice 4

_____

* Taking the reciprocals of numbers with the same sign reverses their order:

2 < 3 but 1/2 > 1/3

An alternate approach to the solution would be to multiply by p:

0.50p < 750 < 1.00p

To solve this requires it be made into two inequalities:

0.50p < 750 ⇒ p < 1500

and

750 < 1.00p ⇒ 750 < p

Then these would need to be recombined to form the answer:

750 < p < 1500

8 0

3 years ago

Faced with rising fax costs, a firm issued a guideline that transmissions of 10 pages or more should be sent by 2-day mail inste

Volgvan

Answer:

a) The calculated value t = 5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

b) p - value 0.00001

The p - value 0.00001 < 0.01

The result is significant at p<0.01

Step-by-step explanation:

Step(i):-

Given mean of the population = 10

Sample size 'n'= 35

Mean of the sample x⁻ = 14.44

Standard deviation of the sample 's' = 4.45

Level of significance ∝ = 0.01

Step(ii):-

Null Hypothesis H₀ : μ >10

Alternative Hypothesis : H₁ : μ < 10

Test statistic

$t = \frac{x^{-} -mean}{\frac{S}{\sqrt{n} } }$

$t = \frac{14.44-10}{\frac{4.45}{\sqrt{35} } }$

t = 5.903

Degrees of freedom = n-1 = 35-1 = 34

tabulated value t₀.₀₁,₃₄ = 2.572

The calculated value t = 5.903 > 2.572 at 0.01 level of significance

Null hypothesis is rejected at 0.01 level of significance

There is a true mean value is less than 10

p- value :

p - value 0.00001

The p - value 0.00001 < 0.01

The result is significant at p<0.01

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3 years ago

Which two activities are examples of data collecting?

slega [8]

Answer:

C and D.

Step-by-step explanation:

In option C, they are collecting data about the lengths of fish in a pond.

In option D, they are collecting data about people's favorite show.

Hope this helps!

If not, I am sorry.

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