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2 years ago

To the nearest tenth, find the approximate distance between points B and D.

Mathematics

2 answers:

ivolga24 [154]2 years ago

7 0

Answer:

Distance = 9.8 units

Step-by-step explanation:

Point B is (-2,5) and point D is (2,-4)

LEts find the distance between these points. USe distance formula

$D=\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

(-2,5) is (x1,y1) and (2,-4) is (x2,y2)

Plug in the values and find out the distance

$D=\sqrt{(x_2-x_1)^2 +(y_2-y_1)^2}$

$D=\sqrt{(2+2)^2 +(-4-5)^2}$

$D=\sqrt{(4)^2 +(-9)^2}$

$D=\sqrt{97}$

Distance = 9.8 units

o-na [289]2 years ago

5 0

The answer is A. 9.8

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The price for strawberries is currently $ 6.40 per pack. next week,strawberries will be on sale at a 20% discount. what is the t

notka56 [123]

Answer:

answer is $5.12

Step-by-step explanation:

Using the formula two and replacing the given values:

Sale Price = Original Price - Amount Saved. So,

Sale Price = 6.40 - 1.28

Sale Price = $5.12 (answer)

This means, the cost of the item to you is $5.12.

You will pay $5.12 for an item with original price of $6.40 when discounted 20%. In other words, if you buy an item at $6.40 with 20% discounts, you pay $6.40 - 1.28 = $5.12

Suppose Have you received a amazon promo code of 1.28. If the price is $6.40 what was the amount saved in percent:

3) 1.28 is what percent off $6.40?

Using the formula two and replacing the given values:

Amount Saved = Original Price x Discount % /100. So,

1.28 = 6.40 x Discount % / 100

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8 0

3 years ago

Show work. This is a BC calculus problem.

stepan [7]

Answer:

Step-by-step explanation:

Remember that the limit definition of a derivative at a point is:

$\displaystyle{\frac{d}{dx}[f(a)]= \lim_{x \to a}\frac{f(x)-f(a)}{x-a}}$

Hence, if we let f(x) be ln(x+1) and a be 1, this will yield:

$\displaystyle{\frac{d}{dx}[f(1)]= \lim_{x \to 1}\frac{\ln(x+1)-\ln(2)}{x-1}}$

Hence, the limit is equivalent to the derivative of f(x) at x=1, or f’(1).

The answer will thus be D.

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2 years ago

Match the expressions with their equivalent simplified expressions.

Tasya [4]

Answer:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}$

Step-by-step explanation:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}$

$\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}$

$\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}$

$\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}$

$\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}$

$\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}$