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3 years ago

Complete the statement. Explain your reasoning 7 3 26 8 4 15 C

Mathematics

2 answers:

Nat2105 [25]3 years ago

7 0

Answer:

m<3=138

Step-by-step explanation:

m<2=42

m<1=m<3

180-42=138

m<1=138 m<3=138

m<1 and m<3 are alternate interior angles

elena-s [515]3 years ago

6 0

Answer:

132 degree

Step-by-step explanation:

a and b are parallel and c is a transversal

so 2 and 3 are interior and they both equal 180

so 3 = 180-48= 132

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Solve for x. 6x-10≤8 or 1/3 x+6>12

Feliz [49]

The solution is

$x\le 3 \:or \:x>18$

$EXPLANATION$

$6x-10\le 8\: or \frac{1}{3}x+6>12$

We group like terms, to obtain;

$6x\le 8+10\: or \frac{1}{3}x>12-6$

Simplify to get,

$6x\le 18\: or \frac{1}{3}x>6$

We further simplify to get;

$x\le 3\: or x>18$

This can also be rewritten as;

$x\le 3, x>18$

$(-\infty 3] \cup (18,+ \infty)$

This can be represented on the number line as shown in the diagram.

6 0

4 years ago

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Which of the following expressions can be written as 12(y – x)

slamgirl [31]

Answer:

I think it would be -12(x-y)?

Step-by-step explanation:

4 0

3 years ago

Find the area of the problem.

Tomtit [17]

Answer:

Step-by-step explanation:

3 times 3 equals 9

9 times 2 equals 18

3 0

3 years ago

What are the zeros of the quadratic function f(x) = 6x2 + 12x - 7?<br>

mina [271]

Answer:

$\frac{-6+\sqrt{78} }{6}$ and $\frac{-6-\sqrt{78} }{6}$

Step-by-step explanation:

We are asked that what are the zeros of the quadratic function f(x) = 6x² +12x -7.

So, we have to find the roots of the equation, f(x) = 6x² +12x -7 =0 ...... (1)

Since the quadratic function can not be factorized, so we have to apply Sridhar Acharya's formula.

This formula gives if, ax² +bx +c =0, the the two roots of the equation are

$\frac{-b+\sqrt{b^{2}-4ac } }{2a} , \frac{-b-\sqrt{b^{2}-4ac } }{2a}$

Therefore, in our case 'a' being 6, 'b' being 12 and 'c' being -7, the two roots of the equation (1) will be

$\frac{-12+\sqrt{12^{2}-4*6*(-7) } }{2*6}, \frac{-12-\sqrt{12^{2}-4*6*(-7) } }{2*6}$

= $\frac{-12+\sqrt{312} }{12},\frac{-12-\sqrt{312} }{12}$

= $\frac{-6+\sqrt{78} }{6}$ and $\frac{-6-\sqrt{78} }{6}$

Hence, x= $\frac{-6+\sqrt{78} }{6}$

and x= $\frac{-6-\sqrt{78} }{6}$

(Answer)

9 0

4 years ago

What is 2/3 divided by 5/6 in simplest form

alexira [117]

Answer:

4/5

Step-by-step explanation:

6 0

3 years ago

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