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emmainna [20.7K]
3 years ago
9

What is 2/3 divided by 5/6 in simplest form

Mathematics
2 answers:
Shalnov [3]3 years ago
7 0

When dividing by a fraction flip the second one over and multiply:

2/3 / 5/6 = 2/3 x 6/5 = (2 x6) / (3x5) = 12/15

12/15 reduces to 4/5

The answer is 4/5

alexira [117]3 years ago
6 0

Answer:

4/5

Step-by-step explanation:

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What is 2+21*13-45+12*67
sleet_krkn [62]

Answer:

1034

Step-by-step explanation:

6 0
2 years ago
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HELP ME!!! 25 POINTS!!
riadik2000 [5.3K]

Answer:

The total distance walked by Paulo is 3750 feet.

Step-by-step explanation:

Here the four points are<em> (-2,1) (-2,-7) (5,-7) (5,1)</em>

Moving from stop A to B, only the y coordinate changes,

the change is ,

=1-(-7) = 1+7 = 8 units

Moving from stop B to C, only the x coordinate changes,

the change is ,

=5-(-2) = 5+2 = 7 units

Moving from stop C to D, only the y coordinate changes,

the change is

=1-(-7) = 1+7 = 8 units

Moving from stop D to A, only the x coordinate changes,

the change is

=5-(-2) = 5+2 = 7 units

Thus, the total distance traveled is 8+7+8+7 = 30 units

It is given that <em>1 unit = 125 feet</em>

Thus, the total distance traveled is = (125)(30) = 3750 feet

The total distance walked by Paulo is 3750 feet.

3 0
3 years ago
May anyone help me out with this question please
tangare [24]
4/52 = 1/13 <== here ya go
6 0
3 years ago
Would someone be able to tell me how to factorise? step by step??
CaHeK987 [17]
1. Factor out the greatest common factor (GCF). (There will not always be one). 2. Count the number of terms.
3. Check to be sure each factor is prime, if not, repeat 1-3.
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5 0
3 years ago
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Consider an object moving along a line with the given velocity v. Assume t is time measured in seconds and velocities have units
Yakvenalex [24]

Answer:

a) positive direction: t < 2s & t>6s   ; negative direction: 2s < t < 6s

b) 7 m

c) 71 m

Step-by-step explanation:

Given:

v(t) = 3t^2 -24t +36   [0 , 7]

Find:

a) The value of time when particle is moving in positive direction:

The change in direction of the particle can be determined by v(t) > 0

Hence,

                                    0 < 3t^2 -24t +36

                                    0 < t^2 - 8t + 12

                                    0 < (t - 2)*(t - 6)

                                    t < 2s  , t  > 6s  

The particle travels in positive direction in the interval t < 2s and t > 6s , While it travels in negative direction when 2s < t < 6s.

b) The displacement ds over the given interval [ 0 , 7 ]

                                  ds = integral (v(t)).dt

                                  ds = t^3 -12t^2 +36t

                                  ds = 7^3 -12*7^2 +36*7

                                  ds = 7 m

c) Total distance traveled in the interval:

                                 Total distance= ds(0-2) + ds(2-6) + ds(6-7)

                                 D = 2*(2^3 -12*2^2 +36*2) - 2*(6^3 -12*6^2 +36*6) + 7

                                 D = 2*32 - 2*0 + 7

                                 D = 71 m          

     

6 0
3 years ago
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