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3 years ago

15

tengo cierta cantidad de caramelos . si los agrupo de a 3 me sobran dos, de a 4 me sobra uno y de a 5 no me sobra ninguno . cuan

tos caramelos puedo tener ? ? ayuda

1 answer:

lys-0071 [83]3 years ago

4 0

Answer:

5 porque 3 mas 2 es 5, 4 mas 1 es 5

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Hi. Please I need help with these questions.

ElenaW [278]

Answer:

Q 12 roots of the equation

$2x^{2} -6+1=0 \\= (x-\frac{\sqrt{10} }{2})(x+\frac{\sqrt{10} }{2})\\$

∝ = $\frac{\sqrt{10} }{2}$

β = $-\frac{\sqrt{10} }{2}$

no matter if u oppose the root

(i) 2( $\frac{\sqrt{10} }{2}$ ) $(-\frac{\sqrt{10} }{2} )^{2}$ +2 $(\frac{\sqrt{10} }{2} )^{2}$ ( $-\frac{\sqrt{10} }{2}$ )+2(

(ii)( $(\frac{\sqrt{10} }{2})^{2}$ - 3 ( $\frac{\sqrt{10} }{2}$ )( $-\frac{\sqrt{10} }{2}$ ) + ( $(-\frac{\sqrt{10} }{2})^{2}$ ) = $\frac{25}{2}$

Q 13 roots of equation

$4x^{2} -3x-4=0\\\alpha = -0.693\\\beta = 1.443$

the roots of the second equation are

x1 = 1/3(-0.693) = -0.231

x2 = 1/3(1.443) = 0.481

the equation is

(x+0.231)(x-0.481)=0

$x^{2}-\frac{1}{4} x-\frac{1}{9}$

4 0

3 years ago

Simplify(3 square root 3 x square root 5 square root of 3)Square root of negative two

Assoli18 [71]

Answer:

9√10 (nine square root ten)

Step-by-step explanation:

(3√3 .√5.√3.)√2

= (3√3*3.√5)√2

=(3*3.√5)√2

=(9√5) √2

=9√5*2

=9√10

8 0

3 years ago

Compare 0.48 and 6/15

Margarita [4]

You could write 6/15 as a decimal 0.40.
Therefore .48>.40

6 0

4 years ago

Read 2 more answers

Help please thanks.

KonstantinChe [14]

Answer:

it would be -18 then 17 cause u distribute the negative sign

7 0

4 years ago

Waht is the difference between 148 and 400

lesya [120]

Difference is subtract so 400-148=252

5 0

3 years ago