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3 years ago

12

point X is located at (2,-6), and point Z is located at (0,5). find the value for the point Y that is located 1/5 the distance f

rom point X to Z.

1 answer:

HACTEHA [7]3 years ago

8 0

Let point is(x,y)
x=(2-0)/5=2/5
y=(-6-5)/5=-11/5
(2/5,-11/5)

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2 years ago

Solve for a.<br> a^2=-3a+88

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Answer:

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Step-by-step explanation:

$a^2=-3a+88$

$a^2+3a=88$

$a^2+3a-88=0$

$x=\frac{-b\pm\sqrt{b^2-4ac} }{2a}$

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