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mariarad [96]
3 years ago
10

A man travels at 42 degrees northwest, and ends up 8.5 miles west of his starting point. How far did he travel?

Mathematics
1 answer:
Zarrin [17]3 years ago
6 0

Answer:

The man traveled 12.70 miles.

Step-by-step explanation:

We can find the distance traveled by the man knowing:

d_{W}: the distance at the west = 8.5 miles

\theta_{NW}: the northwest angle = 42°

Then by using the following trigonometric identity we have:

sin(\theta) = \frac{d_{W}}{d_{NW}}

d_{NW} = \frac{d_{W}}{sin(\theta)} = \frac{8.5 miles}{sin(42)} = 12.70 miles

Therefore, the man traveled 12.70 miles.

I hope it helps you!                                    

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