S = -t³ + 2t² - 2t, 0 ≤ t ≤ 2 Find the body's speed and acceleration at the end of the time interval. *
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The graph of linear equation 2x - 3y = -12 is as shown below.
I this question, we have been given a linear equation 2x - 3y = -12
We need to graph the points.
For x = 1,
2(1) - 3y = -12
2 - 3y = -12
-3y = -14
y = 14/3
For x = 0,
2(0) - 3y = -12
y = (-12)/(-3)
y = 4
For x = -1,
2(-1) - 3y = -12
-3y = -12 + 2
y = (-10) / (-3)
y = 10/3
So, we get coordinates (1, 14/3), (0, 4) and (-1, 10/3)
Now we plot these points.
The graph of linear equation 2x - 3y = -12 is as shown below.
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