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2 years ago

URGENT 20 points describe the graph of the function g(x) =(-0.8 X) is related to the graph of the parent function. *

Mathematics

1 answer:

MAXImum [283]2 years ago

8 0

Answer: G(x) is compressed horizontally and reflected over the y-axis

Step-by-step explanation:simple

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Find the least common multiple of: 12x^3y^2 and 15x^2y^5

allochka39001 [22]

Answer: $60x^3y^5$

Step-by-step explanation:

Least Common Multiple :The least positive number that is a multiple of two or more numbers.

To find : The least common multiple of: $12x^3y^2$ and $15x^2y^5.$

Since, $12x^3y^2=2\times2\times3\times x^3y^2$

$15x^2y^5=3\times5\times x^2y^5$

The least common multiple of: $12x^3y^2$ and $15x^2y^5.$ = $2\times2\times3\times5\times x^3y^5=60x^3y^5$ [take highest power of x and y ]

Hence, the least common multiple of: $12x^3y^2$ and $15x^2y^5.$ = $60x^3y^5$

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3 years ago

X + 4 < 8 HELP please

labwork [276]

Answer:

x + 4 < 8

- 4 -4

x < 4

Step-by-step explanation:

So, Basically anything less than 4 is a solution for this equation.

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2 years ago

What is the difference between -93 and 114 on a number line?

zhenek [66]

Distance: 7-(-3)=10 Midpoint: (7+(-3))=4/2=2 hahaha haha thats right

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2 years ago

Suppose you have a cache of radium, which has a half-life of approximately 1590 years. how long would you have to wait for 1/5 o

lubasha [3.4K]

You would have to wait 318 years for 1/5 (20%) of the Radium to disappear. 1590 is the point where half of the Radium would decay, so if you take 20% of that, it would equate out to 318 years. Radium has a long half life!

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3 years ago

Solve: n/4-1=n/5 .·(>▂<)·.

juin [17]

$\dfrac{n}{4}-1=\dfrac{n}{5}\\
5n-20=4n\\
5n-4n=20\\
n=20$

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3 years ago