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ch4aika [34]
2 years ago
5

Solve for r and t: 6r - 3t = 6 6r + 8t = -16

Mathematics
2 answers:
Tems11 [23]2 years ago
4 0
6r - 3t = 6     /*8
6r + 8t = - 16  /*3

48r - 24t = 48
48r + 24t = - 48
---------------------- + 
96r = 0
r = 0

t = ( -16 + 6r)/8 = - 16/8 = - 2
Slav-nsk [51]2 years ago
3 0
6r - 3t = 6     /*8
6r + 8t = - 16  /*3

48r - 24t = 48
48r + 24t = - 48
---------------------- + 
96r = 0
r = 0

t = ( -16 + 6r)/8 = - 16/8 = - 2




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Answer:

No, because the distance from the origin to point (7 , -7) is greater than the radius of the circle ⇒ 3rd answer

Step-by-step explanation:

From the graph of the circle

∵ The center of the circle F is at the origin

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Let us find the distance between point (7 , -7) and the origin (0 , 0)

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∵ The distance =  \sqrt{(7-0)^{2}+(-7-0)^{2}}=\sqrt{49+49}=\sqrt{98}=7\sqrt{2}

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The correct answer is:

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Answer:

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Answer:

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