The value of x in the congruent triangles abc and dec is 1
<h3>How to determine the value x?</h3>
The question implies that the triangles abc and dec are congruent triangles.
The congruent sides are:
ab = de
bc = ce = 4
ac = cd = 5
The congruent side ab = de implies that:
4x - 1 = x + 2
Collect like terms
4x - x = 2 + 1
Evaluate the like terms
3x = 3
Divide through by 3
x = 1
Hence, the value of x is 1
Read more about congruent triangles at:
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<u>Complete question</u>
Two triangles, abc and cde, share a common vertex c on a grid. in triangle abc, side ab is 4x - 1, side bc is 4, side ac is 5. in triangle cde, side cd is 5, side de is x + 2, side ce is 4. If Δabc ≅ Δdec, what is the value of x? a. x = 8 b. x = 5 c. x = 4 d. x = 1 e. x = 2
When 2n is divided by 4 the remainder will be 2
Division is a simple operation in which a number is divided.
Given,
A whole number n which when divided by 4 gives 3 as remainder
We know,
Dividend = (Divisor × quotient)+ Remainder
Here,
Dividend = n
Quotient = 4
Remainder =3
Consider the divisor as a
Then,
n = 4a+3
Multiply both side by 2
2n= 2(4a+3)
2n= 8a+6
Split the term 6 and take common outside
2n= 8a+4+2
2n= 4(2a+1)+2
So, when 2n is divided by 4
Divisor = 2a+1
Remainder = 2
Hence, when 2n is divided by 4 the remainder will be 2
Learn more about division here
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Answer:
Perimeter of the rectangle=Perimeter of the trapezium
2{(3x+4)+(4x)}=2(5x)+(x-3)+(7x-3)
→2(7x+4)=10x+x-3+7x-3
→14x+8=18x-6
→4x=14
→x=7/2
<u>→</u><u>x=3.5</u>
The value of x is <u>3.5 cm</u>
