Since congruent triangles are the exact same figures, then triangle ABC is the exact same shape as triangle DFE. Hence, as I don't have any additional information to find x, x would be the same for both figures.
Answer:
D 100 revolution is your answer
Answer:
The point is at about (4.5, 100).
Step-by-step explanation:
Minka's line is p = 22t, which has a y-intercept of 0.
Kenji's line is p = 50 + 11t, which has a y-intercept of 50.
Find the line with y-intercept at 0 and the line with y-intercept at 50. Follow the two lines until they intersect. The point of intersection is about (4.5, 100).
You can find this point by setting the two equations equal to each other:
22t = 50 + 11t
Subtract 11t from both sides.
11t = 50
t = 50/11 ≈ 4.545
Then you can find the p value for this point by plugging t = 4.545 into either equation.
p = 22(4.545) = 99.99
p = 50 + 11(4.545) = 99.995
On the graph the point is about (4.5, 100).
An outside angle of a triangle is equal to the sum of the two opposite inside angles.
Using the information in the picture, 132 is an outside angle and x and (3x-24) are the two opposite inside angles.
Setting up the equation you would have: 132 = x + (3x-24)
Now solve for x:
132 = x + (3x-24)
Simplify:
132 = 4x -24
Add 24 to both sides:
156 = 4x
Divide both sides by 4:
x = 156/4
x = 39
