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2 years ago

Triangle ABC is congruent to triangle DFE. Find x.

1 answer:

5 0

Since congruent triangles are the exact same figures, then triangle ABC is the exact same shape as triangle DFE. Hence, as I don't have any additional information to find x, x would be the same for both figures.

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What do x square equal

malfutka [58]

X * x

or

x times x

or

x times itself

or

x squared

all means the same thing

7 0

2 years ago

The formula for the volume of a pyramid is V=(1/3) ⁢B⁢h, where B is the area of the base and h is the height. Rearrange the form

PIT_PIT [208]

To make an equation that solves for the height as according to the volume of a pyramid, you must isolate the variable h on one side.

The first thing you have to do is to multiply both sides by 3 to get 3V=Bh.

Then, divide both sides by B to get your answer as h=3V/B.

6 0

2 years ago

PLSS HELP What is the value of y

Anton [14]

Y= 18 because vertical angles are congruent.

7 0

2 years ago

Read 2 more answers

Assume that two chords in a given circle are congruent. Which of the following must also be true?

o-na [289]

Answer:

If the two chords are congruent, then they must be equidistant from the centre of the circle.

Ans: D

5 0

2 years ago

The quadratic function g(x) = a.ca + bx+c has the

Mumz [18]

<em>The value of b is 14 and the value of c is 65</em>

<h2>Explanation:</h2>

The quadratic function is a function of the form:

$f(x)=ax^2+bx+c$

Here we know that the leading coefficient $a=1$ so we reduce our equation to:

$g(x)=x^2+bx+c$

The roots are those values at which $g(x)=0$

So:

$x^2+bx+c=0 \\ \\ First \ root: \\ \\ (-7+4i)^2+b(-7+4i)+c=0 \\ \\ (-7)^2-2(7)(4i)+(4i)^2-7b+4bi+c=0 \\ \\ 49-56i+16i^2-7b+4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49-56i+16(-1)-7b+4bi+c=0 \\ \\ 49-56i-16-7b+4bi+c=0 \\ \\ 33-56i-7b+4bi+c=0 \\ \\ \\$

$Second \ root: \\ \\ (-7-4i)^2+b(-7-4i)+c=0 \\ \\ (-1)^2(7+4i)^2+b(-7-4i)+c=0 \\ \\ (7)^2+2(7)(4i)+(4i)^2-7b-4bi+c=0 \\ \\ 49+56i+16i^2-7b-4bi+c=0 \\ \\ \\ Simplifying: \\ \\ 49+56i+16(-1)-7b-4bi+c=0 \\ \\ 49+56i-16-7b-4bi+c=0 \\ \\ 33+56i-7b-4bi+c=0$

So we have:

$(1) \ 33-56i-7b+4bi+c=0 \\ \\ (2) \ 33+56i-7b-4bi+c=0 \\ \\ \\ Subtract \ 2 \ from: \\ \\ 33-56i-7b+4bi+c-(33+56i-7b-4bi+c)=0 \\ \\ 33-56i-7b+4bi+c-33-56i+7b+4bi-c=0 \\ \\ \\ Combine \ like \ terms: \\ \\ 33-33-56i-56i-7b+7b+4bi+4bi+c-c=0 \\ \\ -112i+8bi=0 \\ \\ Isolating \ b: \\ \\ b=\frac{112i}{8i} \\ \\ \boxed{b=14}$

Finding c from (1):

$33-56i-7b+4bi+c=0 \\ \\ \\ Substituting \ b: \\ \\ 33-56i-7(14)+4(14)i+c=0 \\ \\ 33-56i-98+56i+c=0 \\ \\ -65+c=0 \\ \\ \boxed{c=65}$

<h2>Learn more:</h2>

Complex conjugate: brainly.com/question/2137496

#LearnWithBrainly

5 0

2 years ago