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NemiM [27]
3 years ago
13

The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = y minus 1 equals StartFract

ion one-fourth EndFraction left-parenthesis x minus 12 right-parenthesis.(x – 12). What is the standard form of the equation for this line?
Mathematics
1 answer:
Illusion [34]3 years ago
3 0

Answer:

x-4y=8

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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3 years ago
Write the equation of the line of best fit using the slope-intercept formula $y = mx + b$. Show all your work, including the poi
Dennis_Churaev [7]

Answer:

y=\frac{5}{7}x+\frac{135}{7}

Step-by-step explanation:

You only need two points on a line to find the equation for that line.

We are going to use 2 points that cross that line or at least come close to. You don't have to use the green points... just any point on the line will work.  You might have to approximate a little.

I see ~(67.5,67.5) and ~(64,65).

Now once you have your points, we need to find the slope.

You may use \frac{y_2-y_1}{x_2-x_1} where (x_1,y_1) \text{ and } (x_2,y_2) are points on the line.

Or you can line up the points vertically and subtract then put 2nd difference over 1st difference.

Like this:

(  64  ,   65  )

-( 67.5, 67.5 )

--------------------

-3.5        -2.5

So the slope is -2.5/-3.5=2.5/3.5=25/35=5/7.

Now use point-slope form to find the equation:

y-y_1=m(x-x_1) where m is the slope and (x_1,y_1) is a point on the line.

y-65=\frac{5}{7}(x-64)

Distribute:

y-65=\frac{5}{7}x-\frac{5}{7}\cdot 64

Simplify:

y-65=\frac{5}{7}x-\frac{320}{7}

Add 65 on both sides:

y=\frac{5}{7}x-\frac{320}{7}+65

Simplify:

y=\frac{5}{7}x+\frac{135}{7}

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What is the slope of a line that goes through the points (-1,2) and (1, 4)?
oksian1 [2.3K]

Answer:

1

Step-by-step explanation:

We can use the slope formula

m = ( y2-y1)/(x2-x1)

    = ( 4-2)/(1 - -1)

    = (4-2)/(1+1)

      = 2/2

    = 1

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Answer:

The answer to the question provided is letter D.

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