Answer:
49 r. 3

the answer is 49 but since three can go into 148 evenly the remainder is 3
Answer:
42.85% or 6/14
Step-by-step explanation:
6 / 14 = 0.428571428571
0.428571428571 * 100 ~ 42.85%
<em>Can I get Brainliest?</em>
Well, we could try adding up odd numbers, and look to see when we reach 400. But I'm hoping to find an easier way.
First of all ... I'm not sure this will help, but let's stop and notice it anyway ...
An odd number of odd numbers (like 1, 3, 5) add up to an odd number, but
an even number of odd numbers (like 1,3,5,7) add up to an even number.
So if the sum is going to be exactly 400, then there will have to be an even
number of items in the set.
Now, let's put down an even number of odd numbers to work with,and see
what we can notice about them:
1, 3, 5, 7, 9, 11, 13, 15 .
Number of items in the set . . . 8
Sum of all the items in the set . . . 64
Hmmm. That's interesting. 64 happens to be the square of 8 .
Do you think that might be all there is to it ?
Let's check it out:
Even-numbered lists of odd numbers:
1, 3 Items = 2, Sum = 4
1, 3, 5, 7 Items = 4, Sum = 16
1, 3, 5, 7, 9, 11 Items = 6, Sum = 36
1, 3, 5, 7, 9, 11, 13, 15 . . Items = 8, Sum = 64 .
Amazing ! The sum is always the square of the number of items in the set !
For a sum of 400 ... which just happens to be the square of 20,
we just need the <em><u>first 20 consecutive odd numbers</u></em>.
I slogged through it on my calculator, and it's true.
I never knew this before. It seems to be something valuable
to keep in my tool-box (and cherish always).
Answer:
C.I. = (2.297, 11.703)
Step-by-step explanation:
The t-statistic for difference of mean is given by,

Here,
= 84
= 7
s₁ = 4
n₁ = 12
s₂ = 6
n₂ = 18
Substituting all value in formula,
We get, t = -3.541 at 28 degree of freedom.
Using this formula, we get, t = 1.5342
Therefore, based on the data provided, the 99% confidence interval for the difference between the population means
is: 2.297 <
< 11.703
which indicates that we are 99% confident that the true difference between population means is contained by the interval (2.297, 11.703)